As soon as I read this, the words "law of cosines" popped
into my head. I don't have a good intuitive feeling for the
law of cosines, but I went and looked it up (you probably
could have done that), and I found that it's exactly what
you need for this problem.
The "law of cosines" relates the lengths of the sides of any
triangle to the cosine of one of its angles ... just what we need,
since we know all the sides, and we want to find one of the angles.
To find angle-B, the law of cosines says
b² = a² + c² - 2 a c cosine(B)
B = angle-B
b = the side opposite angle-B = 1.4
a, c = the other 2 sides = 1 and 1.9
(1.4)² = (1)² + (1.9)² - (2 x 1 x 1.9) cos(B)
1.96 = (1) + (3.61) - (3.8) cos(B)
Add 3.8 cos(B) from each side:
1.96 + 3.8 cos(B) = 4.61
Subtract 1.96 from each side:
3.8 cos(B) = 2.65
Divide each side by 3.8 :
cos(B) = 0.69737 (rounded)
Whipping out the
trusty calculator:
B = the angle whose cosine is 0.69737
= 45.784° .
Now, for the first time, I'll take a deep breath, then hold it
while I look back at the question and see whether this is
anywhere near one of the choices ...
By gosh ! Choice 'B' is 45.8° ! yay !
I'll bet that's it !
Answer:
(4,2)
Step-by-step explanation:
<span>y-intercept when x = 0
so if x = 0, y = -3
answer
</span><span>y-intercept (0, -3)</span>
Using proportions, it is found that it takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct(when both increase or both decrease) or inverse proportional(when one increases and the other decreases, or vice versa), can be built to find the desired measures in the problem, or equations to find these measures.
10 mini-bears weights to 12.1 grams, hence the weight of a mini-bear is of:
12.1/10 = 1.21 grams.
10 regular bears weights to 23.1 grams, hence the weight of a regular bear is of:
23.1/10 = 2.31 grams.
1 super bear weights to 2250 grams, hence the proportion between the <u>weight of a super bear and the weight of a mini-bear</u> is:
2250/1.21 = 1860.
The proportion between the <u>weight of a super bear and the weight of a regular bear</u> is:
2250/2.31 = 974.
The difference of proportions is given by:
1860 - 974 = 886.
It takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.
More can be learned about proportions at brainly.com/question/24372153
#SPJ1
Answer To (b): 10 sandwiches in 20 minutes. But If Your Friend Arrived 10 Minutes Earlier, Then He Can Make 20 Sandwiches In The 20 Minutes That You Are There. If He Started When He Arrived And The Twenty Minutes Started Then, You Can Only Make 5.
