Answer:
1 ¹/₉ hours
Step-by-step explanation:
Let's say L is Larry's speed, C is Curly's speed, and M is Moe's speed.
1 = 2 (L + C)
1 = 1 ⅔ (C + M)
1 = 1 (L + C + M)
Solve the system of equations. First, simplify the equations:
1 = 2L + 2C
3 = 5C + 5M
1 = L + C + M
Double the third equation and subtract the first equation from it:
2 = 2L + 2C + 2M
1 = 2L + 2C
1 = 2M
M = 1/2
Plugging into the second and third equations, we get:
C = 1/10
L = 2/5
Therefore, the time it takes Larry and Moe together is:
1 = t (L + M)
t = 1 / (L + M)
t = 1 / (2/5 + 1/2)
t = 1 / (4/10 + 5/10)
t = 1 / (9/10)
t = 10/9
t = 1 ¹/₉ hours
It takes them 1 ¹/₉ hours, or 1 hour 6 minutes 40 seconds.
Answer:
11.2 minutes
Step-by-step explanation:
If the element decreases by 6.1, every minute, it means that the mass lost every minute = 0.061 x 700g = 42.7g
The mass remaining after a minute = 657.30g
The equation that can be used to solve this question is :
700 - 42.7m = 220
m = minutes
Collect like terms
700 - 220 = 42.7m
480 = 42.7m
divide both sides of the equation by 42.7
m = 11.241218 minutes
the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero
Here, the hundredth is less than 5, so zero would be added to 2. the answer is 11.2 minutes
A) You want to find t such that
.. C(t) = d
.. d = 20 +60*0.95^t
.. (d -20)/60 = 0.95^t
.. log((d -20)/60) = t*log(0.95)
.. t = log((d -20)/60)/log(0.95) . . . . . . time to cool to d degrees (d > 20)
b) C'(t) = 60*0.95^t*ln(0.95)
.. C'(1) = 60*0.95*ln(0.95) ≈ -2.924 °C/min
Since no real values are given for the angles, we will not have an exact angle measurement.
If ∠LPQ is x+28, then that means ∠NPM is the same, since they are vertical angles.
Since ∠QPM is x, then ∠LPN is also x, because they are also vertical angles.
