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Umnica [9.8K]
2 years ago
12

The algebra tiles represent the perfect square trinomial x2 10x c. what is the value of c? c =

Mathematics
1 answer:
devlian [24]2 years ago
6 0

The value of c for which the considered trinomial becomes perfect square trinomial is: 20 or -20

<h3>What are perfect squares trinomials?</h3>

They are those expressions which are found by squaring binomial expressions.

Since the given trinomials are with degree 2, thus, if they are perfect square, the binomial which was used to make them must be linear.

Let the binomial term was ax + b(a linear expression is always writable in this form where a and b are constants and m is a variable), then we will obtain:

(ax + b)^2 = a^2x^2 + b^2 + 2abx

Comparing this expression with the expression we're provided with:

x^2 + 10x + c

we see that:

a^2 = 1 \implies a = \pm 1\\b^2 = 10\\b = \pm 10\\2ab = c\\\pm2(10)1 = c\\c = \pm 20\\

Thus, the value of c for which the considered trinomial becomes perfect square trinomial is: 20 or -20

Learn more about perfect square trinomials here:

brainly.com/question/88561

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A formula for finding P, the perimeter of a rectangle, is P = 2l + 2w, where l is the length of the rectangle, and w is its widt
Varvara68 [4.7K]

Answer:

P=30cm

Step-by-step explanation:

So the formula there is to find the Perimeter of the rectangle, so we are going to use it!

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Hope this helps!

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4 0
3 years ago
A function that models the profit for a new pet-monitoring system shows that there is no profit made until the price reaches $95
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The profits at x = $185 is 0 and the graph is attached below:

<h3>What is graph?</h3>

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

Function is to model the profits of a new pet-monitoring system, so, if the profits are y and x then y = f(x)

The curve shows that y is negative at values of x< $95, then the profits increase when x varies between $95 and $140.

The profits reach a maximum at $140 and then the profits start to reduce as x increases again.

So, the profits at x = $185 is 0.

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