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Norma-Jean [14]
2 years ago
7

Work this out by giving your answer as a fraction 2/3 - 1/2

Mathematics
2 answers:
suter [353]2 years ago
7 0

When subtracting fractions, you need to make sure the denominators are the same. In 2/3 - 1/2, the denominators are different. To make them the same, find the least common denominator. In this case, the common denominator is 6

2/3 becomes 4/6

1/2 becomes 3/6

Now subtract the fractions with the common denominator

4/6 - 3/6 = 1/6

The answer is 1/6

Hope this helps. Please mark me as Brainliest. Thanks!

Hoochie [10]2 years ago
6 0

Answer:

7/6 or 1 1/6

Step-by-step explanation:

First, multiply both denominators so that they are both the same and equal each other. In this case that number is 6. Once they are both have the same denominator, you can add the numerators and keep the same denominator since it's the same thing. So you would add 4 plus 3 and get 7 as your numerator and keep 6 as your denominator,

2/3 = 4/6

1/2= 3/6

4/6 + 3/6 = 7/6 or 1 1/6

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I think it's 138 Long by 109.5 more accurate .
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138/109.5 =1.26
Hence 138 by 109.5 is more proportionate
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John drove 255 miles using 10 gallons of gas. At this rate, how many gallons of gas would he need to drive 411 miles?
Inessa [10]

Answer:

19.6 gallons

Step-by-step explanation:

225/10=441/G

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5 0
3 years ago
Use the given frequency distribution to find the class width, class midpoint, and class boundaries​
Harman [31]

Based on the table attached, the class boundaries are as follows: 43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5.

<h3 /><h3>What is the frequency distribution about?</h3>

Temperature (°F) Frequency

40-44 1

45-49 3

50-54 5

55-59 11

60-64 7

65-69 7

70-74 1

A. Viewing at the frequency table, we find that the lower class limits of two consecutive classes are 40 and 44, respectively. Thus the class width is:

 Class width = 44 − 40= 4

B: One can find the class midpoints by putting the average of the lower and upper class limits. So the midpoint of the first class is  seen below:

=  40  - 44 = \frac{40 + 44}{2}   = 42. In a similar way, we find the rest.

C. The Class boundaries is known to be that which separate the classes removing the class limits. The class boundaries are as follows:

43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5

Therefore, Based on the table attached, the class boundaries are as follows: 43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5.

Learn more about frequency distribution from

brainly.com/question/1094036

#SPJ1

5 0
2 years ago
A man has Rs 1900. he lent some of it at 5% p.a and rest at9% p.a. The total amount of interest which he got after4 years was Rs
Helen [10]

Answer:

The sum is Rs 1,250 and Rs 650

Step-by-step explanation:

Let the amounts be represented as $x and $y

The sum of both is 1900

Thus;

x + y = 1,900 •••••(i)

Mathematically, the interest on the amount borrowed is;

I = PRT/100

where p is the principal, representing the amount borrowed

R is the rate

T is the time

for the first amount of $x ; we have interest as;

I = (x * 5 * 4)/100 = 20x/100

for the second, we have

I = (y * 9 * 4)/100 = 36y/100

The sum of both is 580

Thus;

20x/100 + 36y/100 = 580

20x + 36y = 58000 •••••(ii)

From equation i;

x = 1,900 - y

Substitute this into equation ii

We have this as;

20(1900-y) + 36y = 58,000

38000 - 20y + 36y = 58,000

16y = 58000 - 38000

16y = 20,000

y = 20,000/16

y = 1250

From equation 1;

x + y = 1900

x = 1900-y

x = 1900-1250

y = 650

4 0
2 years ago
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