D because it says you will be getting at least 4500 or more dollars by adding the adult and student tickets
Answer: 20
Step-by-step explanation:
all you need to do is substitute the variables into the given expression, y-5b would turn into 5-5(-3) then you solve and you get 5-(-15) = 5+15 = 20, so youre answer is 20
Step-by-step explanation:
it is a rectangle (usually).
so,
2×length + 2×width = 80
therefore, length + width = 40
length×width = 384
length = 384/width
384/width + width = 40
384 + width² = 40×width
width² - 40×width + 384 = 0
the general solution for such a square equation is
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
x = width
a = 1
b = -40
c = 384
width = (40 ± sqrt((-40)² - 4×1×384))/(2×1) =
= (40 ± sqrt(1600 - 1536))/2 =
= (40 ± sqrt(64))/2 = (40 ± 8)/2 =
= 20 ± 4
width1 = 20 + 4 = 24 cm
length1 = 40 - 24 = 16 cm
width2 = 20 - 4 = 16 cm
length2 = 40 - 16 = 24 cm
so, both solutions are the same.
the greeting card is 24×16 cm. or 16×24, depending on how you are holding it.
Answer:
First term=3
Second term =-2
Third term=18
Fourth term=-62
Fifth term=258
Sixth term=-1022
Step-by-step explanation:
an=(-4)^(n-1) + 2
First term: a1=(-4)^(1-1) + 2
a1=(-4)^0+2
a1=1+2
a1=3
Second term:a2=(-4)^(2-1)+2
a2=(-4)^(1)+2
a2=-4+2
a2=-2
third term:a2=(-4)^(3-1)+2
a2=(-4)^(2)+2
a2=-4 x -4 + 2
a2=16+2
a2=18
Fourth term: a4=(-4)^(4-1)+2
a4=(-4)^3 +2
a4=-4x-4x-4+2
a4=-64+2
a4=-62
Fifth term:a5=(-4)^(5-1)+2
a5=(-4)^4+2
a5=-4x-4x-4x-4+2
a5=256+2
a5=258
6th term:a6=(-4)^(6-1)+2
a6=(-4)^5+2
a6=-4x-4x-4x-4x-4+2
a6=-1024+2
a6=-1022
