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kipiarov [429]
3 years ago
11

Can someone help me please

Mathematics
1 answer:
iris [78.8K]3 years ago
6 0

Answer:

"I can find the maximum or minimum by looking at the factored expression of a quadratic function by reading off its roots and taking the arithmetic average of them to obtain the x-coordinate of the quadratic function, and then substituting that value into the function."

Step-by-step explanation:

Because of the symmetry of quadratics (which is the case here because we have two factors of degree 1, so we are dealing with a <em>polynomial</em> of degree 2, which is a fancy way of saying that something is a quadratic), the x-coordinate of the extremum (a fancy way of saying maximum or minimum) is the (arithmetic) average of the two roots.

In the factored form of a quadratic function, we can immediately read the roots: 3 and 7. Another way to see that is to solve (x-3)(x-7)=0, which gives x-3=0 \vee x-7=0 (the 'V' stands for 'or'). We can take the average of the two roots to get the x-coordinate of the minimum point of the graph (which, in this case, is x=\frac{3+7}{2} = \frac{10}{2} = 5).

Having the x-coordinate of the extremum, we can substitute this value into the function to obtain the maximum or minimum point of the graph, because that will give the y-coordinate of the extremum.

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2. Lab groups of three are to be randomly formed (without replacement) from a class that contains five engineers and four non-en
Anna11 [10]

Answer:

The number of different lab groups possible is 84.

Step-by-step explanation:

<u>Given</u>:

A class consists of 5 engineers and 4 non-engineers.

A lab groups of 3 are to be formed of these 9 students.

The problem can be solved using combinations.

Combinations is the number of ways to select <em>k</em> items from a group of <em>n</em> items without replacement. The order of the arrangement does not matter in combinations.

The combination of <em>k</em> items from <em>n</em> items is: {n\choose k}=\frac{n!}{k!(n-k)!}

Compute the number of different lab groups possible as follows:

The number of ways of selecting 3 students from 9 is = {n\choose k}={9\choose 3}

                                                                                         =\frac{9!}{3!(9 - 3)!}\\=\frac{9!}{3!\times 6!}\\=\frac{362880}{6\times720}\\ =84

Thus, the number of different lab groups possible is 84.

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Step-by-step explanation:

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abbie spent 5/8 of her money and saved the rest. if she spent 45,how much money did she have at first?
algol13

$72

<h3>Further explanation</h3>

<u>Given:</u>

Abbie spent ⁵/₈ of her money and saved the rest.

She spent $45.

<u>Question:</u>

How much money did she have at first?

<u>The Process:</u>

The meaning of "Abbie spent ⁵/₈ of her money" is that she has spent 5 of the 8 parts of the money she had at first.

Let us make a pattern of 8 units for the amount of money that Abbie had at first.

\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}

Since Abbie spent ⁵/₈ of her money, then we create a pattern of 5 units containing $9 each. Recall that \boxed{\$ 45 \div 5 = \$ 9}

\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9} = \$ 45

From the pattern above, we can see that \boxed{ \ 1 \ unit = \$ 9 \ }.

Let us calculate how much money Abbie had at first.

\boxed{ \ 1 \ unit = \$ 9 \ }

\boxed{ \ 8 \ unit = \ ? \ }

\boxed{ \ 8 \times \$ 9 = \$ 72 \ }

Thus, the money Abbie had at first is $72.

The complete pattern of Abbie's initial money is as follows:

\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9} = \$ 72

- - - - - - - - - -

<u>Quick Steps:</u>

Let M as Abbie's initial money.

\boxed{ \ \frac{5}{8} \times M = \$ 45 \ }

Both sides are multiplied by ⁸/₅ so that M is the subject alone on the left side.

\boxed{ \ M = \frac{8}{5} \times \$ 45 \ }

We crossed out 5 and 45.

\boxed{ \ M = 8 \times \$ 9 \ }

\boxed{ \ M = \$ 72 \ }

Thus, the money Abbie had at first is $72.

<h3>Learn more</h3>
  1. How much did Ciro spend altogether for the concert ticket, hotel, and dinner? brainly.com/question/12507869
  2. How much does his cat weigh (Jesse's)? brainly.com/question/388037
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Keywords: Abbie, spent 5/8 of her money, saved the rest, $45, $72, how much money, she have at first, the pattern

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Step-by-step explanation:

6 · 0.08 = 0.48

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