Let us say that:
a = ones
b = fives
c = twenties
So that the total money is:
1 * a + 5 * b + 20 * c = 229
=> a + 5b + 20c = 229 -->
eqtn 1
We are also given that:
c = a – 5 -->
eqtn 2
a + b + c = 30 -->
eqtn 3
Rewriting eqtn 3 in terms of b:
b = 30 – a – c
Plugging in eqtn 2 into this:
b = 30 – a – (a – 5)
b = 35 – 2a -->
eqtn 4
Plugging in eqtn 2 and 4 into eqtn 1:
a + 5(35 – 2a) + 20(a – 5) = 229
a + 175 – 10a + 20a – 100 = 229
11a = 154
a = 14
So,
b = 35 – 2a = 7
c = a – 5 = 9
Therefore there are 14 ones, 7 fives, and 9 twenties.
Answer:
Step-by-step explanation:
4(2+5q) = 8 + 20q
8 + 20q = 1
20q = -7
q = -7/20
Answer:
1.97-20= -18.03
20-1.97= 18.03
Step-by-step explanation:subtract the numbers from each other.
Answer:
x = 3.464
Step-by-step explanation:
7x^2 - 84 = 0
7x^2 = 84
x^2 = 12
x= 3.464
I believe it's 15, but correct me if I'm wrong
This is because there is one 10 in 15. This gives you 3 tens and 5 in the ones.
