Surface Area of A Cylinder.
As=2(3.14)rh+2(3.14)r^2
Radius: 6in
Height: 9 in
Plug it in:
2(3.14)(6)(9)+2(3.14)(6^2)
6.28(54)+6.28(36)
339.12+226.08= 565.2
Therefore, it will take about 565.2in^2 of wrapping paper to cover the whole present.
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Assuming this is some kind of modular question, maybe mod 17.
since 1+8+9=1, we can say that 8+9=0
therefore, 2+0=x, so x=2