B. each system works independently to stabilize the body
Answer:
C. A metal ion takes the place of the hydrogen of an acid
Explanation:
When an acid react with base neutralization reaction take place.
During neutralization reaction water and salt are formed.
For example;
Base sodium hydroxide react with hydrochloric acid and form sodium chloride and water.
The sodium hydroxide consist of sodium metal ion in the form of Na⁺ and OH⁻. when it react with acid hydrogen atom of acid replace by sodium metal and react with anion of acid and form salt called sodium chloride.
Chemical equation:
NaOH + HCl → NaCl + H₂O
Answer:
Explanation:
Hello, in this case, the lead is catching heat and the water losing it, that's why the heat relation ship is (D is for Δ):
Now, by stating the heat capacity definition:
Solving for the equilibrium temperature:
Which is very close to the water's temperature since the lead's both mass and head capacity are lower than those for water.
Best regards.
Answer:
11.9 moles Cl₂
Explanation:
To find the number of moles, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = constant (0.0821 L*atm/mol*K)
-----> T = temperature (K)
Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.
P = 33.3 atm R = 0.0821 L*atm/mol*K
V = 11.5 L T = 120. °C + 273.15 = 393.15 K
n = ? moles
PV = nRT
(33.3 atm)(11.5 L) = n(0.0821 L*atm/mol*K)(393.15 K)
382.95 = n(0.0821 L*atm/mol*K)(393.15 K)
382.95 = (32.2776)n
11.9 = n
Answer:
Amount of pyridine required = 0.0316 M
Explanation:
pH of a buffer solution is calculated by using Henderson - Hasselbalch equation.
![pH=pK_a+log\frac{[Conjugate\ base]}{[weak\ acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2Blog%5Cfrac%7B%5BConjugate%5C%20base%5D%7D%7B%5Bweak%5C%20acid%5D%7D)
Pyridinium is a weak acid and in the presence of its conjugate base, it acts as buffer.
Henderson - Hasselbalch equation for pyridine/pyridinium buffer is as follows:
![pH=pK_a+log\frac{[Py]}{PyH^+]}](https://tex.z-dn.net/?f=pH%3DpK_a%2Blog%5Cfrac%7B%5BPy%5D%7D%7BPyH%5E%2B%5D%7D)
pH = 4.7
(Pyridinium)=0.100 M
Substitute the values in the formula
![pH=pK_a+log\frac{[Py]}{PyH^+]}\\4.7=5.2 log\frac{[Py]}{0.100}](https://tex.z-dn.net/?f=pH%3DpK_a%2Blog%5Cfrac%7B%5BPy%5D%7D%7BPyH%5E%2B%5D%7D%5C%5C4.7%3D5.2%20log%5Cfrac%7B%5BPy%5D%7D%7B0.100%7D)
![4.7-5.2=log\frac{[Py]}{0.100} \\-0.5=log\frac{[Py]}{0.100}\\\frac{[Py]}{0.100}=antilog -0.5\\\frac{[Py]}{0.100}=0.316](https://tex.z-dn.net/?f=4.7-5.2%3Dlog%5Cfrac%7B%5BPy%5D%7D%7B0.100%7D%20%5C%5C-0.5%3Dlog%5Cfrac%7B%5BPy%5D%7D%7B0.100%7D%5C%5C%5Cfrac%7B%5BPy%5D%7D%7B0.100%7D%3Dantilog%20-0.5%5C%5C%5Cfrac%7B%5BPy%5D%7D%7B0.100%7D%3D0.316)
![\frac{[Py]}{0.100} =0.316](https://tex.z-dn.net/?f=%5Cfrac%7B%5BPy%5D%7D%7B0.100%7D%20%3D0.316)
[Py]=0.0316\ M
Amount of pyridine required = 0.0316 M
