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xenn [34]
3 years ago
7

Ozone decomposes to oxygen according to the equation 2 O3(g) → 3 O2(g). Write the equation that relates the rate expressions for

this reaction in terms of the disappearance of O3 and the formation of oxygen.
Chemistry
1 answer:
Roman55 [17]3 years ago
7 0

Answer:

Check explanation.

Explanation:

The rate of reaction can be defined as the speed at which concentration of Reactant(s) is/are being converted into product(s) or it can be defined as the rate at which the concentration of Reactant(s) disappear and the rate at which the product(s) forms.

For instance, in the Example below;

aA + bB-------> cC + dD. Where a,b,c and d are the number of moles of A,B,C and D respectively.

The rate of Reaction can be expressed as; - 1/a d[A]/dt = –1/b d[B]/dt= 1/c d[C]/dt =1/d d[D]/dt.

So, back to the question; we are given the balanced equation of,

===> 2 O3(g) --------> 3 O2(g).

Rate of disappearance of ozone,O3 is:

= -∆[O3]/ ∆t.

= -1/2 [O3]/∆t.

Where t= time and the [O3} is the concentration of ozone,O3.

Note that we have the negative sign because, ozone is been consumed/used up in the reaction.

==> The rate of the formation of oxygen is ;

= ∆[O2]/∆t.

= 1/3 ∆[O2]/∆t.

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What is the specific heat capacity of an unknown metal if 75.00 g of the metal absorbs 418.6J of heat and the temperature rises
EleoNora [17]

Answer:

The specific heat capacity of the unknown metal is 0.223 \frac{J}{g*C}

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • Q= 418.6 J
  • c= ?  
  • m= 75 g
  • ΔT= 25 C

Replacing:

418.6 J= c* 75 g* 25 C

Solving:

c=\frac{418.6 J}{75 g*25 C}

c= 0.223 \frac{J}{g*C}

<u><em>The specific heat capacity of the unknown metal is 0.223 </em></u>\frac{J}{g*C}<u><em></em></u>

<u><em> </em></u>

<u><em></em></u>

3 0
2 years ago
A 50.0 mg sample of iodine-131 was placed in a container 32.4 days ago. if its half-life is 8.1 days, how many milligrams of iod
sertanlavr [38]

3.124mg of I-131 is present after 32.4 days.

The 131 I isotope emits radiation and particles and has an 8-day half-life. Orally administered, it concentrates in the thyroid, where the thyroid gland is destroyed by the particles.

What is Half life?

The time required for half of something to undergo a process: such as. a : the time required for half of the atoms of a radioactive substance to become disintegrated.

Half of the iodine-131 will still be present after 8.1 days.

The amount of iodine-131 will again be halved after 8.1 additional days, for a total of 8.1+8.1=16.2 days, reaching (1/2)(1/2)=1/4 of the initial amount.

The quantity of iodine-131 will again be halved after 8.1 more days, for a total of 16.2+8.1+8.1=32.4 days, to (1/4)(1/2)(1/2)=1/16 of the initial quantity.

If the original dose of iodine-131 was 50mg, the residual dose will be (50mg)*(1/16)=3.124mg after 32.4 days.

Learn more about the Half life of radioactie element with the help of the given link:

brainly.com/question/27891343

#SPJ4

7 0
1 year ago
If 6.02×1023 atoms of element Y have a mass of 28.09 g, what is the identity of Y?
Mazyrski [523]

Silicon is the element having a mass of 28.09 g

<u>Explanation</u>:

  • Silicon is the element having an atomic mass of 28.09 g / mol. So 28.09 g of silicon contains 6.023 \times 10^23 atoms. One mole of each element can produce one mole of compound.
  • The Atomic weight of an element can be determined by the number of protons and neutrons present in one atom of that element. So atomic weight expressed in grams always contain the same number of atoms( 6.023 \times10^23).
  • Avagadro number is the number of atoms of 1 mole of any gas at standard temperature and pressure. It has been determined that 6.023 \times 10^23 atoms of an element are equal to the average atomic mass of that element.
8 0
3 years ago
El gas dióxido de carbono ocupa un volumen de 10, 5 litros a 20°C ¿Cuál será el volumen que ocupará el gas si la temperatura Cel
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Answer:

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6 0
3 years ago
How many orbitals surround the nucleus in a neutral atom of sulfur (S)?
Leto [7]
<h2>C</h2>

Explanation:

The atomic number of S is 16

So,number of electrons in S is 16

The electronic configuration of S is 2,8,6

The orbital electronic configuration of S is ^{1}s_{2}^\text{ }^{2}s_{2}^\text{ }^{2}p_{x2}^\text{ }^{2}p_{y2}^\text{ }^{2}p_{z2}^\text{ }^{3}s_{2}^\text{ }^{3}p_{x2}^\text{ }^{3}p_{y1}^\text{ }^{3}p_{z1}^\text{ }

So,the number of orbitals involved is 9.

3 0
3 years ago
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