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xenn [34]
3 years ago
7

Ozone decomposes to oxygen according to the equation 2 O3(g) → 3 O2(g). Write the equation that relates the rate expressions for

this reaction in terms of the disappearance of O3 and the formation of oxygen.
Chemistry
1 answer:
Roman55 [17]3 years ago
7 0

Answer:

Check explanation.

Explanation:

The rate of reaction can be defined as the speed at which concentration of Reactant(s) is/are being converted into product(s) or it can be defined as the rate at which the concentration of Reactant(s) disappear and the rate at which the product(s) forms.

For instance, in the Example below;

aA + bB-------> cC + dD. Where a,b,c and d are the number of moles of A,B,C and D respectively.

The rate of Reaction can be expressed as; - 1/a d[A]/dt = –1/b d[B]/dt= 1/c d[C]/dt =1/d d[D]/dt.

So, back to the question; we are given the balanced equation of,

===> 2 O3(g) --------> 3 O2(g).

Rate of disappearance of ozone,O3 is:

= -∆[O3]/ ∆t.

= -1/2 [O3]/∆t.

Where t= time and the [O3} is the concentration of ozone,O3.

Note that we have the negative sign because, ozone is been consumed/used up in the reaction.

==> The rate of the formation of oxygen is ;

= ∆[O2]/∆t.

= 1/3 ∆[O2]/∆t.

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A ------------ ----------------- is the dying out of a large number of species on a global scale
ziro4ka [17]

Answer:

Extinction event or sometimes known as Mass extinction

Explanation:

These events typically are typically widespread and rapid decrease in the biodiversity (which takes into account spread and existence of current species). The worst mass extinction was Permian–Triassic extinction where over 90% of species of organisms vanished.

5 0
3 years ago
The amount of a chemical solution is measured to be 2 liters.
irinina [24]
2 liters may be 1.5 to 1.9 rounded up to 2 or 2.1 or 2.4 rounded down to 2.

2 - 1.5 = 0.5

percent error = (absolute error / quantity) * 100

percent error = 0.5/2 * 100% = 0.25 * 100% = 25%

Choice C. 25%.
3 0
3 years ago
A sample of gas contains 0.1500 mol of HCl(g) and 7.500×10-2 mol of Br2(g) and occupies a volume of 9.63 L. The following reacti
Furkat [3]

Answer:

9.63 L.

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

2HCl(g) + Br_2(g)\rightarrow 2HBr(g) + Cl_2(g)

So the consumed amounts of hydrochloric acid and bromine are the same to the beginning based on:

n_{Br_2}^{consumed}=0.1500molHCl*\frac{1molBr_2}{2molHCl}=0.075molBr_2

In such a way, the yielded moles of hydrobromic acid and chlorine are:

n_{HBr}=0.1500molHCl*\frac{2molHBr}{2molHCl}=0.1500molHBr \\n_{Cl_2}=0.1500molHCl*\frac{1molCl_2}{2molHCl}=0.075molCl_2

Thus, the volume of the sample, after the reaction is the same as no change in the total moles is evidenced, that is 9.63L.

Best regards.

7 0
3 years ago
If 5,800 j of energy are applied to a 15.2 kg piece of lead, by how much does the temp change if the specific heat of lead is 0.
scoray [572]

Answer:

The answer will be 2.98K

Explanation:

Using the formula:

Q = mc∆T

Q= 5,800 (heat in joules)

m= convert 15.2kg to g which is 15200g (mass in grams)

c= 0.128 J/g °c (Specific heat capacity)

∆T=  what we need to find (temperature change)

5800J = 15200g x 0.128 x ∆T

= 2.98K  

7 0
3 years ago
How many grams of potassium (K) contain 5.11 x 10^22 atoms of potassium?
Darina [25.2K]

The atomic mass of K is 39

from Avogadro's law

39g of K contains 6.02x10^23 atoms

therefore if

39=6.02x19^23

X=5.11×10^22

making X the subject of the formula

X= (5.11×10^22×39)÷6.02×10^23

X= 33g

7 0
2 years ago
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