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xenn [34]
3 years ago
7

Ozone decomposes to oxygen according to the equation 2 O3(g) → 3 O2(g). Write the equation that relates the rate expressions for

this reaction in terms of the disappearance of O3 and the formation of oxygen.
Chemistry
1 answer:
Roman55 [17]3 years ago
7 0

Answer:

Check explanation.

Explanation:

The rate of reaction can be defined as the speed at which concentration of Reactant(s) is/are being converted into product(s) or it can be defined as the rate at which the concentration of Reactant(s) disappear and the rate at which the product(s) forms.

For instance, in the Example below;

aA + bB-------> cC + dD. Where a,b,c and d are the number of moles of A,B,C and D respectively.

The rate of Reaction can be expressed as; - 1/a d[A]/dt = –1/b d[B]/dt= 1/c d[C]/dt =1/d d[D]/dt.

So, back to the question; we are given the balanced equation of,

===> 2 O3(g) --------> 3 O2(g).

Rate of disappearance of ozone,O3 is:

= -∆[O3]/ ∆t.

= -1/2 [O3]/∆t.

Where t= time and the [O3} is the concentration of ozone,O3.

Note that we have the negative sign because, ozone is been consumed/used up in the reaction.

==> The rate of the formation of oxygen is ;

= ∆[O2]/∆t.

= 1/3 ∆[O2]/∆t.

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Data:

<span>Solute: 28.5 g of glycerin (C3H8O3)
Solvent: 135 g of water at 343 k.
Vapor pressure of water at 343 k: 233.7 torr.

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Raoult's Law: </span><span><span>The vapour pressure of a solution of a non-volatile solute is equal to the vapour pressure of the pure solvent at that temperature  multiplied by its mole fraction.

Formula: p = Xsolvent * P pure solvent

X solvent = moles solvent / moles of solution

molar mass of H2O = 2*1.0g/mol + 16.0 g/mol = 18.0 g/mol

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moles of solute = 28.5 g / 92.0 g/mol = 0.310 mol

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Xsolvent = 7.50mol / 7.81mol = 0.960

p = 233.7 torr * 0.960 = 224.4 torr

Answer: 224.4 torr
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The reaction 2no2 ? 2no + o2 follows second-order kinetics. at 300 °c, [no2] drops from 0.0100 m to 0.00650 m in 100.0 s. the ra
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