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4 years ago

How many moles of gas are present in 57.20 L of argon at a pressure of 1 atm and a temperature of 0°C?

Chemistry

1 answer:

slamgirl [31]4 years ago

3 0

Answer:

n= 2.55 moles

Explanation:

Using the formula of ideal gas law:

PV = nRT

nRT=PV

n= PV/RT

n= number of moles

R= Avogadro constant = 0.0821

T= Temperature in K => ºC + 273.15 K

V= volume in L

P= pressure in atm

n= (1 atm)(57.20 L) / (0.0821)(237.15 K)

n= 2.50 moles

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Gasoline is a mixture of hydrocarbons, a major component of which is octane, CH3CH2CH2CH2CH2CH2CH2CH3. Octane has a vapor pressu

Nitella [24]

Answer:

$\Delta \:H_{vap}=40383.88\ J/mol$

Explanation:

The expression for Clausius-Clapeyron Equation is shown below as:

$\ln P = \dfrac{-\Delta{H_{vap}}}{RT} + c$

Where,

P is the vapor pressure

ΔHvap is the Enthalpy of Vaporization

R is the gas constant (8.314×10⁻³ kJ /mol K)

c is the constant.

For two situations and phases, the equation becomes:

$\ln \left( \dfrac{P_1}{P_2} \right) = \dfrac{\Delta H_{vap}}{R} \left( \dfrac{1}{T_2}- \dfrac{1}{T_1} \right)$

Given:

$P_1$ = 13.95 torr

$P_2$ = 144.78 torr

$T_1$ = 25°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (25 + 273.15) K = 298.15 K

$T_1$ = 298.15 K

$T_2$ = 75°C = 348.15 K

So,

$\ln \:\left(\:\frac{13.95}{144.78}\right)\:=\:\frac{\Delta \:H_{vap}}{8.314}\:\left(\:\frac{1}{348.15}-\:\frac{1}{298.15}\:\right)$

$\Delta \:H_{vap}=\ln \left(\frac{13.95}{144.78}\right)\frac{8.314}{\left(\frac{1}{348.15}-\frac{1}{298.15}\right)}$

$\Delta \:H_{vap}=\frac{8.314}{\frac{1}{348.15}-\frac{1}{298.15}}\left(\ln \left(13.95\right)-\ln \left(144.78\right)\right)$

$\Delta \:H_{vap}=\left(-\frac{863000.86966\dots }{50}\right)\left(\ln \left(13.95\right)-\ln \left(144.78\right)\right)$

$\Delta \:H_{vap}=40383.88\ J/mol$

4 0

3 years ago

For the following reaction, calculate how many moles of each product are formed when 4.05 g of water is used.

timurjin [86]

Answer:

A. 0.225 mole of H₂

B. 0.113 mole of O₂.

Explanation:

We'll begin by calculating the number of mole in 4.05 g of water (H₂O). This can be obtained as follow:

Mass of H₂O = 4.05 g

Molar mass of H₂O = (2×1) + 16 = 2 + 16 = 18 g/mol

Mole of H₂O =?

Mole = mass /Molar mass

Mole of H₂O = 4.05 / 18

Mole of H₂O = 0.225 mole

Next, the balanced equation.

2H₂O —> 2H₂ + O₂

From the balanced equation above,

2 moles of H₂O produced 2 moles of H₂ and 1 mole of O₂.

A. Determination of the number of mole hydrogen produced.

From the balanced equation above,

2 moles of H₂O produced 2 moles of H₂.

Therefore, 0.225 mole of H₂O will also produce 0.225 mole of H₂.

B. Determination of the number of mole oxygen produced.

From the balanced equation above,

2 moles of H₂O produced 1 mole of O₂.

Therefore, 0.225 mole of H₂O will produce = (0.225 × 1)/2 = 0.113 mole of O₂.

Thus, 0.113 mole of O₂ is produced.

7 0

3 years ago

the reaction a(g) ⇌ b(g) has an equilibrium constant that is less than one. what can you conclude about ∆g° for the reaction?

-Dominant- [34]

For this reaction: ΔG⁰>0.

Balanced chemical reaction A(g) ⇌ (g)

ΔG° indicates that all reactants and products are in their standard states.

ΔG° = R·T·lnK.

ΔG° is Gibbs free energy

T is the temperature on the Kelvin scale

R is the ideal gas constant

The equilibrium constant (K) is the ratio of the partial pressures or the concentrations of products to reactants.

Gibbs free energy (G) determines if reaction will proceed spontaneously, nonspontaneously or in equilibrium processes.

If K < 1, than ΔG° > 0.

Reactants (in this example A) are favored over products (in this example B) at equilibrium.

More about equilibrium: brainly.com/question/25651917:

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4 0

1 year ago

For this ionic compound, what would be the name of the anion? Ca(NO3)2

Ne4ueva [31]

Idk if it's correct but I guess it's calcite (c)

4 0

3 years ago

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The radius of a lithium atom is 130 picometers, and the radius of a fluorine atom is 60 picometers. The radius of a lithium ion,

natali 33 [55]

Answer:

A positive ions is always smaller than the corresponding atom.

A negative ion is always larger than the corresponding atom.

Explanation:

The reason for this is that, when a positive ion is formed, a full shell is usually removed with its electrons thereby reducing the size of the electron cloud and decreasing the size of the electron cloud.

A negative ion is formed by addition of more electrons to the electron cloud hence it spreads out. Interelectronic repulsion accounts for the larger size of the negative ion.

3 0

3 years ago