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Leokris [45]
2 years ago
6

______11. 3 and -3 are _____.

Mathematics
1 answer:
bagirrra123 [75]2 years ago
3 0

Answer:

11=B. or A

12=C

13=B

im sure in number 13

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You invest $5000 in an account at 5.5% per year simple interest. How much will you have in the account at the beginning of the 6
NeX [460]

Answer:

The amount in the account in the  beginning of the 6th year is $6375 .

Step-by-step explanation:

Formula

Simple\ interest = \frac{Principle\times Rate\ times Time}{100}

As given

You invest $5000 in an account at 5.5% per year simple interest.

Principle = $ 5000

Rate = 5.5 %

Time = 5 years

(As calculate amount in the account for beginning of 6th year.)

Putting all the values in the formula

Simple\ interest = \frac{5000\times 5.5\times 5}{100}

Simple\ interest = 50\times 5.5\times 5

Simple interest = $ 1375

Amount =  Principle + Simple interest

Putting values in the above formula

Amount =  $5000 + $1375

Amount = $ 6375

Therefore the amount in the account in the  beginning of the 6th year is $ 6375 .

8 0
3 years ago
22. A parabola equation is given as y = 3(x - 2)^2 + 5. What are the coordinates of the vertex?
sergiy2304 [10]

Answer:

(2, 5)

Step-by-step explanation:

The x coordinate is the number inside the parentheses, but with the opposite sign, 2

The y coordinate is the number at the end

5 0
3 years ago
Read 2 more answers
5-6(a+2)=7+a<br> What is a
iogann1982 [59]
Remmeber you can do anything to an equaiton as long as you do it to btoh sides
5-6(a+2)=7+a
distribute
5-6a-12=7+a
add like terms
-6a-7=7+a
add 6a both sides
-7=7+7a
minus 7 both sides
-14=7a
divide by 7
-2=a
a=-2
5 0
3 years ago
Read 2 more answers
Select the correct answer from each drop-down menu.
nikitadnepr [17]

Angle D and angle B are equal.

5 0
3 years ago
Define the function
miss Akunina [59]

Given that

g(x) = x^3 + x

the inverse g^{-1}(x) is such that

g\left(g^{-1}(x)\right) = g^{-1}(x)^3 + g^{-1}(x) = x

or

g\left(f(x)\right) = f(x)^3 + f(x) = x

Differentiating both sides using the chain rule gives

3f(x)^2f'(x) + f'(x) = 1 \\\\ f'(x) \left(3f(x)^2+1\right) = 1 \\\\ f'(x) = \dfrac1{3f(x)^2+1}

Then the derivative of <em>f</em> at 2 is

f'(2) = \dfrac1{3f(2)^2+1} = \boxed{\dfrac14}

7 0
2 years ago
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