Question 2) The measures of the angles of a triangle
1 answer:
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Step-by-step explanation:
Let AB be 5cm
AC be 13cm
According to Pyathagros therom
AC²=AB²+BC²
13²=5²+BC²
169=25+BC²
BC²=169-25
BC²=144
BC=√144
BC=12cm
Area of ∆ABC=½×base×hight
=½×12×5
=½×60
=30cm²
Parimeter of ∆ABC=a+b+c
=5+12+13
=30cm
