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andrew11 [14]
3 years ago
14

Billy owns a painting that is valued at $39,113. If the value of the artwork increases by 10%

Mathematics
1 answer:
Bingel [31]3 years ago
5 0

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$39113\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.1\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{every year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &11 \end{cases} \\\\\\ A=39113\left(1+\frac{0.1}{1}\right)^{1\cdot 11}\implies A=39113(1.1)^{11}\implies A\approx 111593.95

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Answer:

(q+\frac{11}{2})^2-\frac{121}{4}

Step-by-step explanation:

We have been given an expression q^2+11q. We are asked to complete the square to make a perfect square trinomial. Then, write the result as a binomial squared.

We know that a perfect square trinomial is in form a^2+2ab+b^2.

To convert our given expression into perfect square trinomial, we need to add and subtract (\frac{b}{2})^2 from our given expression.

We can see that value of b is 11, so we need to add and subtract (\frac{11}{2})^2 to our expression as:

q^2+11q+(\frac{11}{2})^2-(\frac{11}{2})^2

Upon comparing our expression with (a+b)^2=a^2+2ab+b^2, we can see that a=q, 2ab=11q and b=\frac{11}{2}.

Upon simplifying our expression, we will get:

(q+\frac{11}{2})^2-\frac{11^2}{2^2}

(q+\frac{11}{2})^2-\frac{121}{4}

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3 + 5 = 8   Remember, this is positive 8. (+8)

<u>3. Put that term at the end of the equation. </u>

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-5n + 8  This is our answer!

Just to prove it works:

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