Question

A child has 12 blocks, of which 6 are black, 4 are red, 1 is white and 1 is blue. All blocks of the same color are identical. If the child puts the blocks in a line, how many arrangements are possible?

Answer 1

The arrangement of the blocks is an illustration of permutation and combination

The number of possible arrangement is 27720 ways

How to determine the number of arrangements

The given parameters are:

n = 12

Black = 6

Red = 4

White = 1

Blue = 1

The number of possible arrangement is then calculated as:

$Ways = \frac{12!}{6!4!1!1!}$

Evaluate the factorials

$Ways = 27720$

Hence, the number of possible arrangement is 27720 ways

Read more about permutation and combination at:

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