Question

A source charge of 5. 0 µC generates an electric field of 3. 93 × 105 at the location of a test charge. How far is the test charge from the source charge?.

Answer 1

Answer:

r = 0.338 meters

Explanation:

Q = Source charge

q = Test charge

5μC= 5*10^-6 C

Start with the electric field equation:

$E = \frac{F}{q}$

and Coulombs law

$F=\frac{k|Qq|}{r^2}$

Combining these functions we get:

$E=\frac{k|Q|}{r^2}$

As you can see the test charge cancels so we do not need the value of it.

Plug in your numbers:

$3.93*10^5=\frac{(8.99*10^9)(5*10^-^6)}{r^2}$

solve for r

$r=\sqrt{\frac{(8.99*10^9)(5*10^-^6)}{(3.93*10^5)} }$

$r= 0.338 meters$