Answer:
't' lies in the interval (0.2476, 4.038)
Explanation:
Given:
The function for temperature (T) as:
Now, according to the condition given in the question
or
or
or
6t>(1.4t² + 1.4)
or
(1.4t² + 1.4 - 6t) < 0
on solving the quadratic
we get the intervals as:
t = 0.2476 and t = 4.038
Therefore, the <u>'t' lies in the interval (0.2476, 4.038)</u>
14t^2-80t+28<0
7t^2-40t+14<0
Solve by quadratic:
t=[ 40+/-sqr(1600-4*7*14)]/14
=.375 or 5.340
These are the boundaries.
So the temperature is over 100 in the interval (.375, 5.340) hrs.
The freezing point is the strait line at 55 degrees Celsius
Answer:
mag aral ka bubu
Explanation:
ang tanga mu hahahahhaha luko nandyan lang naman yan hahahhahahahahahahhahahahahahahahhahahahahahaahahahahahahahhahahahahahahahahahahahahaahhahahaahahhaahha09561782
All of the forces listed are correct. There are 4 presently known forces.
Second question os B. the Lorentz force. It's given by
F=q(E+VxB) where q is the electric charge, E is the electric field, V is the particle's velocity vector, B is the magnetic flux density, and "x" represents the vector cross product.
Answer:
The distance from the top of the stick would be 2l/3
Explanation:
Let the impulse 'FΔt' acts as a distance 'x' from the hinge 'H'. Assume no impulsive reaction is generated at 'H'. Let the angular velocity of the rod about 'H' just after the applied impulse be 'W'. Also consider that the center of percussion is the point on a bean attached to a pivot where a perpendicular impact will produce no reactive shock at the pivot.
Applying impulse momentum theorem for linear momentum.
FΔt = m(Wl/2), since velocity of center of mass of rod = Wl/2
Similarly applying impulse momentum theorem per angular momentum about H
FΔt * x = I * W
Where FΔt * x represents the impulsive torque and I is the moment of inertia
F Δt.x = (ml² . W)/3
Substituting FΔt
M(Wl/2) * x = (ml². W)/3
1/x = 3/2l
x = 2l/3
