Question

5. The load across a battery consists of two resistors, with values of 15 Ohm and 45 Ohm connected in series.

Answer 1

a) $60 \Omega$

The total resistance of resistors connected in series is equal to the sum of the individual resistances:

$R=R_1 + R_2 + .... + R_n$

In this problem, we have two resistors connected in series:

$R_1 = 15 \Omega$

$R_2 = 45 \Omega$

So the total resistance of the circuit is

$R=R_1 + R_2 = 15 \Omega + 45 \Omega = 60 \Omega$

b) 6.0 V

The relationship between voltage, current and resistance of a circuit is given by Ohm's law

$V=RI$

where

V is the voltage

R is the total resistance

I is the current

In this circuit, we have

$R=60 \Omega$ is the total resistance

I = 0.1 A is the current

So, the voltage of the battery is

$V=(60 \Omega)(0.1 A)=6.0 V$