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Katen [24]
2 years ago
14

Solve this system of equations.

Mathematics
2 answers:
PIT_PIT [208]2 years ago
8 0

Answer:

(8,0)

Step-by-step explanation:

y= 0.50x - 4

y= -0.25x + 2

I changed it to make it:

0.25x + y = 2

-0.50x + y = -4

--

We subtract the y's and every equation to cancel out the y.

0.25x - (-0.50x) = 0.75x

2-(-4)=6

0.75x = 6

x = 8.

Plug the x into either equation. We'll do the first eqn.

0.25(8)+y=2

2 = y = 2

y = 0.

(8,0).

nata0808 [166]2 years ago
3 0

x = 8, y = 0

y=\frac{1}{2}x-4

y=-\frac{1}{4}x+2

We substitute y=\frac{1}{2}x-4 into the y for y=-\frac{1}{4}x+2, and we get:

\frac{1}{2}x-4 = -\frac{1}{4}x+2

+\frac{1}{4}x   +\frac{1}{4}x

\frac{3}{4}x -4 = 2

  +4  +4

\frac{3}{4}x = 6

(4)\frac{3}{4}x = 6 (4)

The 4's cross out and we get:

3x = 24

/3     /3

x=8

Not we substitute x(8) into one of our original equations: y=\frac{1}{2}x-4

y=\frac{1}{2}x-4

y=\frac{1}{2}(8)-4

y=4-4

y-0

We get our final answer: (8,0)

Hope that helps!

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Nesterboy [21]

Answer:  The Expression is Equivalent, However, NOT completely factored.

Step-by-step explanation:

3x^2     -     12  

Following:

3 ( x^2    -    4   )

Factor:

3x^2   -  12

Factor Out Common Term 3:

3 ( x^2    -  4  )  =  3 (x^2  -  4 )

Factor:

x^2  -  4

( x  +   2 )  ( x   -  2 )

Answer:

3 ( x  +  2) ( x  -  2)

Hence, The Expression is Equivalent, However,  Wasn't Completely Factored.

Hope that helps!

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alekssr [168]

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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
irga5000 [103]

Answer:

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

y = -16x^2 + 177x + 98

It hits the ground when y = 0, so we have to find x for which y = 0, which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

y = -16x^2 + 177x + 98

-16x^2 + 177x + 98 = 0

So

a = -16, b = 177, c = 98

\bigtriangleup = 177^{2} - 4(-16)(98) = 37601

x_{1} = \frac{-177 + \sqrt{37601}}{2*(-16)} = -0.53

x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

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