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Colt1911 [192]
2 years ago
10

Pls help I need this done asap​

Mathematics
1 answer:
Bezzdna [24]2 years ago
3 0

Would you like me to add them separately or should i add both answer together after?

Step-by-step explanation:

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A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui
Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= \frac{dx}{dt}=1. 8 m/s

\triangle ABD\sim\triangle ECD

Therefore, \frac{AB}{EC}=\frac{BD}{CD}

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xy=24

Differentiate w.r.t t

x\frac{dy}{dt}+y\frac{dx}{dt}=0

x\frac{dy}{dt}=-y\frac{dx}{dt}

\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}

When the man is 4 m from  the building

Then, we have x=12-4=8 m

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y=\frac{24}{8}=3

Substitute the values then we get

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Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0
3 years ago
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