Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
It would be Adjacent/hypotenus which is 36/39 and when simplified the answer is 12/13
Answer:
x < 3 or x > 9
Step-by-step explanation:
given 6| x - 6 | + 7 > 25 ( subtract 7 from both sides )
6| x - 6 | > 18 ( divide both sides by 6 )
| x - 6 | > 3
Inequalities of the form | x | > a always have solutions of the form
x < - a OR x > a, hence
x - 6 < - 3 or x - 6 > 3 ( add 6 to both sides in both inequalities )
x < 3 or x > 9
