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Colt1911 [192]
3 years ago
10

Pls help I need this done asap​

Mathematics
1 answer:
Bezzdna [24]3 years ago
3 0

Would you like me to add them separately or should i add both answer together after?

Step-by-step explanation:

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Plz help me solve this question ASAP without using algebra, Thank u‼️
VashaNatasha [74]

Let cost of 1 box of red pen = x

Let cost of 1 box of black pen = y

Gaga bought 5 red box and her sister 4 black box then total cost is given by

5x+4y

Given that total cost was $44

so equation will be 5x+4y=44...(i)

After exchange

Gaga= 4 red box + 1 Black box

Sister = 1 red box + 3 Black box

then cost for Gaga = 4x+1y

cost for sister = 1x+3y

Given that cost for both after exchange is same so we get

4x+1y = 1x+3y

or 4x-1x = 3y-1y

or 3x = 2y

or 3x/2=y ...(ii)

plug (ii) into (i)

5x+4y=44

5x+4(3x/2)=44

5x+12x/2=44

5x+6x=44

11x=44

x=4

Now plug value of x into (ii)

y=3x/2=3*4/2=12/2=6

Hence cost of 1 box of red pen = $4

And cost of 1 box of black pen = $6

---

If you want to get solution without solving both equations then just graph both equations and find the intersection point.

You will see that graph intersect at (4,6) which gives x=4, y=6

6 0
3 years ago
Y’all pls help me :(
Ilia_Sergeevich [38]

Answer: B

Step-by-step explanation:

When you are multiplying exponents, if the base is the same, then you can directly add the exponents together.

We can see that both bases are 6. That means we can add the exponents.

3+\frac{1}{4}                             [common denominator]

\frac{12}{4}+\frac{1}{4}                            [add]

\frac{13}{4}

Now, we know that the answer will be 6^1^3^/^4.

6 0
4 years ago
Pls I need help with this last question I’m almost done pls answer 28
Stells [14]
If the question is referring to the least common multiple it is 24
6 0
3 years ago
Read 2 more answers
Find the product of (–d + e)(4e + d). Which statements are true? Check all that apply.
yulyashka [42]
In equation, (-d + e)( 4e + d) will be (-4ed - d^2 + 4e^2 +ed ) to simplify we combine the terms with the same variables such as d^2, e^2 and ed. The equation becomes, 4e^2 - 3ed - d^2 . The product has 3 terms with a degree of 2. The statements that are true are B and E.
3 0
3 years ago
Read 2 more answers
One car traveled 220 miles and drove 10 mph hour slower than a second car which drove 260 miles. If the cars were traveling for
Colt1911 [192]
55 mph...if the 1st one drove 260 miles, that's 65mph for 4 hours...1st car has to be 55mph for 4 hours to get 220 miles.
3 0
3 years ago
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