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lara31 [8.8K]
2 years ago
6

Z^2+1+y when y=4, and z=3.

Mathematics
1 answer:
OlgaM077 [116]2 years ago
7 0
3^2+1+4=14 the answers 14
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Y=1x+2 (you don’t have to write the 1 in front of the x so you can write it as y=x+1)
6 0
3 years ago
What is the following quotient? 2- 8sqr / 4+12 sqr
AlekseyPX

Answer: 130

Step-by-step explanation:

--> first solve sqr-->2-64/4+144

-->perform division next as per DMAS rule-->64÷4=16--> 2-16+144

--> now perform addition and subtraction-->2-16-14--> -14+144= 130

7 0
3 years ago
Plz help i need this soon​
wlad13 [49]

Answer:

b= (m)(-150)

Step-by-step explanation:

1800-1350 = 450

450/3 = 150

b= m*-150

7 0
3 years ago
Solve by using Pythagorean Theorem, a= 5, b= x-1, and c=x
charle [14.2K]

The value of x is 13, from the values of x the values of a,b and c becomes 5, 12 and 13, which is obtained by using Pythagorean theorem.

Step-by-step explanation:

The given is,

             a = 5

             b = x - 1

             c = x

Step:1

      Pythagorean theorem is,

              a^{2} + b^{2} = c^{2}................................(1)

      (  It states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides )

      From the given values the equation (1) becomes,

                       5^{2} + (x-1) ^{2} = x^{2}

                             ( (a-b)^{2} = a^{2}  + b^{2} -2ab )

               25 + ( x^{2} + 1 - 2x ) = x^{2}

                           25 + 1 -2x = 0               ( ∵ Eliminate x^{2} in both sides)

                                     26 = 2x

                                       x = 13

Step:2

        From the values of x,

                   a = 5

                    b = ( 13 - 1 ) = 12

                   c = 13

Result:

            The value of x is 13, from the values of x the values of a,b and c becomes 5, 12 and 13, which is obtained by using Pythagorean theorem.

3 0
3 years ago
(-16,-4),(8,-2) in a graph NOWW!!!!
Charra [1.4K]

Answer:

Hope this helps

6 0
2 years ago
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