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cupoosta [38]
2 years ago
9

A basketball team took a total of 100 shots. One player took 70% of all 100 shots, and

Mathematics
2 answers:
ipn [44]2 years ago
6 0

Answer:

10 shots

Step-by-step explanation:

If there are 100 shots, then 70% is 70 shots. If she/he made 60% then she missed 10 because 70-60=10

NemiM [27]2 years ago
4 0

The player took a total of 70 shots and missed about 28 shots.

<h3>Percentage</h3>

Percentage is used in expressing a fraction number or decimal in fraction of 100. It is expressed using the '%' sign.

Given a total shot of 100, since the player took 70% of the shot, hence:

Total shot taken by the player = 70% of 100 = 0.7 * 100 = 70 shots.

Total shot shot missed = (100% - 60%) of 70 = 40% of 70 = 0.4 * 70 = 28 shots.

The player took a total of 70 shots and missed about 28 shots.

Find out more on Percentage at: brainly.com/question/24304697

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-2x + y=5 and -5x + y = -4 cooridbnates of the solution to this system of equation
Viktor [21]

Answer:

(3,11)

Step-by-step explanation:

Turn both equations into linear equations:

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Then, just graph both equations.

Find the point where the two lines intersect. That point of intersection is  the solution. That coordinate is (3,11).

8 0
3 years ago
6. An ostrich cannot fly, but it is able to run fast. Suppose an ostrich runs east for 7.95 s and then runs 161 m south, so that
Liula [17]

Answer:

159 m

Step-by-step explanation:

From the information given:

It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.

Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.

Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.

We are to find, the magnitude of the ostrich's eastward component.

i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.

Using the Pythagoras rule:

ES² = OE² + OS²

226² = OE² + 161²

226² -  161² = OE²

OE²  =  226² -  161²

OE²  = 51076 - 25921

OE²  =  51076 - 25921

OE²  =  25155

OE = \sqrt{25155}

OE =  158.60 m

OE ≅ 159 m

Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.

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3 years ago
There is a 10% chance of rain tomorrow. A spinner with 10 sections is spun to simulate the probability of rain. If the results a
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While in the experimental one the average is 42%

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