Well if they’re getting a quarter of it, they’re receiving 500, 500 divided by 2 is 250 so I would guess A
Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
\left[x \right] = \left[ \frac{-1}{4}\right][x]=[4−1] = x*3 +3x*2+6) - (9x*2-5x+7
Multiply -12 to each of the terms (make sure to carry the negative!)
-36a - 24b + 12 will be your final answer :)
The answer is c
This is because only the y-int changes
