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pochemuha
4 years ago
15

Find the length of x. Round to the nearest tenth

Mathematics
1 answer:
damaskus [11]4 years ago
6 0
Asked and answered elsewhere.
brainly.com/question/9535488
You might be interested in
Explain how to use a horizontal number line<br> to order four fractions from least to greatest.
horsena [70]

Answer:

To order fractions from least to greatest, start by finding the lowest common denominator for all of the fractions. Next, convert each of the fractions by dividing the lowest common denominator by the denominator and then multiplying the top and bottom of the fraction by your answer.

Step-by-step explanation:

Solution for the above problem: We first find the least common denominator by finding the least common multiple for 4, 3, 2, 6, and 8. We find the LCM by the prime factorization method. Next, place the fractions in order from least to greatest.

4 0
3 years ago
4x − 8y = –20<br> 4x − 7y = –15
Alja [10]
Y = 5
x = 5
good luckkkkkkk
8 0
3 years ago
Which shows two expressions that equivalent ​
AveGali [126]

Answer:

Option A is the answer...

-7*-15*-5=-525

-7*-75=-525

-1*525=-525

6 0
3 years ago
The formula for calculating the density of an object is D=-, where m is mass and v is volume.
Over [174]

Answer:

M= D x V, V= M x D

Step-by-step explanation:

You just do the opposite of division since the original is:

Density= Mass/ Volume

8 0
4 years ago
Can someone help me with this question????
frutty [35]

Answer:

Hi! I think I got the answer, it is a tricky one! The answer I got was C) 1029.

Step-by-step explanation:

1. It is good to first know that 40%more means 1.4 (some number). So, if n is 40% more than the sum of the other three numbers: n= 1.4* (<em>l +m+p)</em> .

2. Also note that: <em>n+l+m+p= </em>1764; so, <em>n = 1764-l-m-p.</em>

3. Since we have two expressions for n, we can equate them to each other. Giving, 1.4* (<em>l +m+p) =1764-l-m-p . </em>Simplifying we get 2.4 (<em>l +m+p)</em>=1764.

4. <em>l +m+p =1764/2=735.</em>

5. 1764-735=1029

Hope that helps! Feel free to message back if there are any questions!

<em />

7 0
3 years ago
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