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pentagon [3]
3 years ago
10

Mark put his dog on a diet. The dog's total weight change for the first 2 weeks was -3/4

Mathematics
2 answers:
KengaRu [80]3 years ago
8 0
It changed 6 pounds differnce
sveta [45]3 years ago
5 0
7 days in one week so times 7/1 by -3/4= so that's 5 1/4
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Which polynomial represents the sum below?
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Read 2 more answers
Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that th
11111nata11111 [884]

Answer:

The null hypothesis is H_0: \mu = 14

The alternate hypothesis is H_a: \mu < 14

The test statistic is t = -1.95.

The p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

Step-by-step explanation:

Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that their highlighters could write continuously for 14 hours.

At the null hypothesis, we test if the mean is 14 hours, that is:

H_0: \mu = 14

At the alternate hypothesis, we test if the mean is less than 14 hours, that is:

H_a: \mu < 14

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

14 is tested at the null hypothesis:

This means that \mu = 14

X = 13.6 hours, s = 1.3 hours. Sample of 40:

In addition to the values of X and s given, we have that n = 40

Test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{13.6 - 14}{\frac{1.3}{\sqrt{40}}}

t = -1.95

The test statistic is t = -1.95.

P-value:

The p-value of the test is the probability of finding a sample mean lower than 13.6, which is a left tailed test, with t = -1.95 and 40 - 1 = 39 degrees of freedom.

Using a calculator, the p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

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2 years ago
Then find the area S of the region.<br><br> y=2 x^2, y^2=1/2 x
r-ruslan [8.4K]

Recall that the area under a curve and above the x axis can be computed by the definite integral.  If we have two curves

<span>        y = f(x) and y = g(x)</span>

such that 

<span>        f(x) > g(x) 
</span>
then the area between them bounded by the horizontal lines x = a and x = b is


To remember this formula we write

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3 years ago
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