1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Klio2033 [76]
2 years ago
15

Can someone help me with this

Mathematics
1 answer:
Misha Larkins [42]2 years ago
3 0

Answer:

Statements                                                                       Justifications

E bisects AI, BC bisects AE, FH bisects EI                     Given

AE is congruent to EI                                                       Definition of Bisector

AD is congruent to DE                                                     Definition of Bisector

EG is congruent to GI                                                       Definition of Bisector

If AE is congruent to EI, AD is congruent to DE, and EG is congruent to GI, then AD is congruent to DE, EG, and GI, DE is congruent to AD, EG, and GI, EG is congruent to AD, DE, and GI, and GI is congruent to AD, DE, and EG. Therefore, AD is congruent to EG.

This isn't the best answer and probably won't get you a 100, but it shows effort so...

You might be interested in
Peter is writing a number in scientific notation.The number is grater that ten million and less that one hundred million.Which e
OLga [1]

Answer:

M  =  a \times 10^7  where 1 < a ≤ 9

The EXPONENT USED BY PETER is 7 in all the possible cases.

Step-by-step explanation:

Let us assume the needed number is M.

Also, given:

The needed number is GREATER than 10 Million.

⇒ M  > 10 Million

⇒ M > 10,000,000

⇒ M > 1 \times 10^7  ...... (1)

The needed number is SMALLER than 100 Million.

⇒ M  <  100 Million

⇒ M < 100,000,000

⇒ M  <  1 \times 10^8  ...... (2)

Comparing (1) and (2) we can see that M can have more than 7 zeroes after 1 but LESS than 8 zeroes after 1.

So, the possible values of M can be:

M  =  a \times 10^7  where 1 < a ≤ 9

So, the EXPONENT USED BY PETER is 7 in all the possible cases.

5 0
3 years ago
In a triangle, the measure of the second angle is twice the measure of the first angle. The
Olegator [25]
B. X,2X,3X cuz the sum of X and 2X is 3X
3 0
3 years ago
I need help x-x please
KengaRu [80]


60 - 45 = 15
so 15/45 = p/100

answer is A.
6 0
3 years ago
Every whole number is a real number . <br> True or false
grandymaker [24]
True. No imaginary number is considered "whole", all whole numbers are rational and real.
8 0
3 years ago
Read 2 more answers
--<br> Choose the correct simplification of the expression -5x2(4x – 6x2 – 3).
natali 33 [55]

\huge \bf༆ Answer ༄

Let's simply ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: - 5 {x}^{2} (4x - 6 {x}^{2}  - 3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:( - 5x {}^{2}  \times 4x) - ( - 5 {x}^{2}  \times 6 {x}^{2} ) - ( - 5 {x}^{2}  \times  3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: - 20 {x}^{3}    - ( - 30 {x}^{4} ) - ( - 15 {x}^{2} )

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: - 20 {x}^{3}  + 30 {x}^{4}  + 15 {x}^{2}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:30 {x}^{4}  - 20 {x}^{3}  + 15 {x}^{2}

5 0
2 years ago
Other questions:
  • How do I find the values of x and y
    6·1 answer
  • Isabel measured the length of each type of bead she used to make a key ring. She recorded the measurements in a line plot. Isabe
    14·1 answer
  • 2х + Зу = 9
    12·1 answer
  • Brawdy Plastics, Inc., produces plastic seat belt retainers for General Motors at the Brawdy Plastics plant in Buffalo, New York
    7·1 answer
  • What does −|−9| mean
    8·1 answer
  • PLEASE HELP!! thanks :)
    10·1 answer
  • 4. The school's soccer team is made up of 3 grades. Grade 10s make up 17% of the team
    5·1 answer
  • Complete the table so a linear function is represented. SHOW ALL WORK!
    5·1 answer
  • PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    6·2 answers
  • I need this algrba hw done by tonight! It’s easy 40 points!
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!