Answer:
It is 0.873 but rounded to hundredth is 0.87
Step-by-step explanation:
expression: (3.24-3/8+7/9-0.15) divided by 4
Solve: (3.24+7/9-3/8-0.15) divided by 4
= (3.24+0.78-0.375-0.15) divided by 4
=3.49/4
-0.873 = 0.87 to the nearest hundred
degress celcius
The volume of a sphere refers to the number of cubic units that will exactly fill a sphere. The volume of a sphere can be found or calculate by using the formula V=4/3πr^3, where r represents the radius of the figure.
In this exercise is given that a sphere has a radius of 4 centimeters and it is asked to find its volume and use 3.14 as the value of π or pi. The first step would be substitute the values into the previous mention formula.
V=4/3πr^3
V=4/3(3.14)(4 cm)^3
V=4/3)(3.14)(64 cm^3)
V=267.9 cm^3
The volume of the sphere is 267.9 cubic centimeters.
Answer:
3.3 and 4.5
Step-by-step explanation:
Answer:
Part a) The slant height is ![3\sqrt{2}\ units](https://tex.z-dn.net/?f=3%5Csqrt%7B2%7D%5C%20units)
Part b) The lateral area is equal to ![54\sqrt{2}\ units^{2}](https://tex.z-dn.net/?f=54%5Csqrt%7B2%7D%5C%20units%5E%7B2%7D)
Step-by-step explanation:
we know that
The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces
so
![LA=6[\frac{1}{2}(b)(l)]](https://tex.z-dn.net/?f=LA%3D6%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28l%29%5D)
where
b is the length side of the hexagon
l is the slant height of the pyramid
Part a) Find the slant height l
Applying the Pythagoras Theorem
![l^{2}=h^{2} +a^{2}](https://tex.z-dn.net/?f=l%5E%7B2%7D%3Dh%5E%7B2%7D%20%2Ba%5E%7B2%7D)
where
h is the height of the pyramid
a is the apothem
we have
![h=3\ units](https://tex.z-dn.net/?f=h%3D3%5C%20units)
![a=3\ units](https://tex.z-dn.net/?f=a%3D3%5C%20units)
substitute
![l^{2}=3^{2} +3^{2}](https://tex.z-dn.net/?f=l%5E%7B2%7D%3D3%5E%7B2%7D%20%2B3%5E%7B2%7D)
![l^{2}=18](https://tex.z-dn.net/?f=l%5E%7B2%7D%3D18)
![l=3\sqrt{2}\ units](https://tex.z-dn.net/?f=l%3D3%5Csqrt%7B2%7D%5C%20units)
Part b) Find the lateral area
![LA=6[\frac{1}{2}(b)(l)]](https://tex.z-dn.net/?f=LA%3D6%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28l%29%5D)
we have
![b=6\ units](https://tex.z-dn.net/?f=b%3D6%5C%20units)
![l=3\sqrt{2}\ units](https://tex.z-dn.net/?f=l%3D3%5Csqrt%7B2%7D%5C%20units)
substitute the values
![LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}](https://tex.z-dn.net/?f=LA%3D6%5B%5Cfrac%7B1%7D%7B2%7D%286%29%283%5Csqrt%7B2%7D%29%5D%3D54%5Csqrt%7B2%7D%5C%20units%5E%7B2%7D)
Sorry, not sure how to describe it, but the lower the temperature, the higher the hot chocolate sales.