Evaluate the expression.<br><br><br><br> 10+83÷16

Julia has 4 gallons 2 quarts of water.Ally needs the same amount of water but only has 12 quarts.How much more water does Ally n

denis-greek [22]

Well there are 4 quarts to a gallon and 4 / 12 = 3 so she has 3 gallons so she needs 1 gallon and 2 quarts
so the answer is 1Gallon and 2Quarts

7 0

4 years ago

Surface Area of Cylinder=2πrh+2πr2

Alex

Find the surface area when r is 8 inches and h is 8 inches.

$\qquad$ A. 160π in²

$\qquad$ B. 154π in²

$\qquad$ C. 288π in²

$\qquad$ D. 256π in² ☑

We are given –

$\qquad$ ⇢Radius of cylinder , r = 8 inches

$\qquad$ ⇢ Height of cylinder, h = 8 inches.

We are asked to find surface area of the given cylinder.

Formula to find the surface cylinder given by –

$\bf \star \pink{ Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2 }$

Now, Substitute given values –

$\sf \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2$

$\sf \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2 \pi \times 8 \times 8 + 2\pi \times 8^2$

$\sf \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2 \pi \times 8^2 + 2\pi \times 8^2$

$\sf \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2\pi \times 64 +2\pi \times 64$

$\sf \twoheadrightarrow Surface\: Area_{(Cylinder)} =128 \pi + 128\pi$

$\purple{\bf \twoheadrightarrow Surface\: Area_{(Cylinder)} = 256\pi \: in^2 }$

Henceforth,Option D is the correct answer.

8 0

2 years ago

Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

5 0

3 years ago

Kevin needs 1,000 ribbons for a school event. Each ribbon has to be 2.25 feet long. Tell how Kevin can use a pattern to find how

marysya [2.9K]

2.25 x 1000 = 2250.

That's how much yds of ribbons he needs.

7 0

3 years ago

If the cost of a dress is $75.00 and

11Alexandr11 [23.1K]

Answer:

80%

Step-by-step explanation:

Original price =$75.00

Sale price =$60.00

The percentage discount can be calculated by dividing the sale price by the original price multiplied by 100%.

So % discount = $60.00/$75.00 x 100%

0.8 x 100%

80%

Janelle got the dress on a discount of 80%.

This is so because she got the dress for a price less than the original price

6 0

2 years ago

Evaluate the expression. 10+83÷16