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3 years ago

14

What is the distance between A(1,1) and B(7,-7) using the distance formula? Thanks(:

1 answer:

Arisa [49]3 years ago

7 0

Let's say that d is distance, and the formula is as follows;
d= $\sqrt{(x_{2}- x_{1} ) ^{2}+ (y_{2}- y_{1} ) ^{2}$

This means that with the values filled in we have an equation that looks like;
$d= \sqrt{(7-1)^{2}+(-7-1)^{2}}$

Therefore solving would look like;
$d= \sqrt{(7-1)^{2}+(-7-1)^{2}} 

d= \sqrt{(6)^{2}+(-8)^{2}} 

d= \sqrt{36+64} 

d= \sqrt{100}$ or 10

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BartSMP [9]

Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

$\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}$

so distance between A(-5,4) and B(3,4) is:

$\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}$

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For B(3,4) and C(3,-5).

$\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}$

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

$\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}$

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

$\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}$

so fourth bush 9 units below of A.

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1 year ago

A total of 300 pine and maple trees will be planted in a park. There will be 2 pine trees planted for every 3 maple trees plante

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Answer:

120

Step-by-step explanation:

2 of every 5 trees are pine trees.

2/5 · 300 = 120

120 pine trees are going to be planted in the park.

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I wanna say the answer is A

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