This is 6th grade math if y’all could help

PLEASE HELP NOW!!!<br> QRST is a square. Use the properties of a square to find the value of x.

Annette [7]

Answer:

x = 6

Step-by-step explanation:

QRST is a square.

QR = RS (sides of a square are equal)

7x - 10 = 5x + 2

7x - 5x = 10 + 2

2x = 12

x = 12/2

x = 6

7 0

2 years ago

One vertex of a triangle is located at (0, 5) on a coordinate grid. After a transformation, the vertex is located at (5, 0). Whi

madreJ [45]

Answer:

The Transformations are R(O , -90°) & R(O , 270)

Step-by-step explanation:

* Lets revise the rotation of a point

- If point (x , y) rotated about the origin by angle 90° anti-clock wise

∴ Its image is (-y , x)

- If point (x , y) rotated about the origin by angle 90° clock wise

(270° anti-clockwise or -90°)

∴ Its image is (y , -x)

- If point (x , y) rotated about the origin by angle 180°

∴ Its image is (-x , -y)

* There is no difference between rotating 180° clockwise (-180°) or

anti-clockwise (180°) around the origin

* Lets solve the problem

∵ One vertex of a triangle is located at (0, 5) on a coordinate grid

∵ The image of the point after the transformation is (5 , 0)

- The coordinates are switched with each other

∴ There is no rotation with 180° or -180° because in the rotation with

180° and -180° around the origin we change only the signs of the

coordinates without switch them

∴ There is a rotation with 90° are 270° or -90°

- The zero has no sign

- When we rotate the point (0 , 5) by -90° or 270° around the origin

we will change the sign of x-coordinate and switch the two

coordinates

∴ The image of the point is (y , -x)

∵ x = 0 and y = 5

- There is no sign for zero, so we switch the coordinates only

∴ The vertex is located at (5, 0)

∴ The Transformations are R(O , -90°) & R(O , 270)

3 0

3 years ago

Read 2 more answers

A portion of a roller coaster track is shown in the figure above. the roller coaster track is shown at ground level at point S a

eimsori [14]

Answer:

Step-by-step explanation:

This is classic right triangle trig. The height of the hill is 78.4 which serves as the side opposite the reference angle of 23 degrees. The side we are looking for is the hypotenuse of that triangle. The trig ratio that relates the side opposite a reference angle to the hypotenuse of the right triangle is the sin ratio. Setting it up using our values:

$sin(23)=\frac{78.4}{x}$ , where x is the unknown length of the hypotenuse. Solving for x: