Answer:
Ok, so we have a square with sides of 14 inches. :)
The diagonal splits the square into two by the corners, so it forms two right triangles!
We can use the Pythagorean theorem on the right triangle to get:
14^2 + 14^2 = x^2
BTW, x is the length of the diagonal :)
So, 196 + 196 = x^2 = 392
Sooo, x is just the square root of 392 :)
= 19.7989898732, which rounds to 20
Step-by-step explanation:
Sample space, S = {(1,1),(1,3),(1,4),(1,5),(1,6),(1,8),(2,1),(2,3),(2,4),(2,5),(2,6),(2,8),(2,1),(2,3),(2,4),(2,5),(2,6),(2,8),(3,1),(3,3),(3,4),(3,5),(3,6),(3,8),(3,1),(3,3),(3,4),(3,5),(3,6),(3,8),(4,1),(4,3),(4,4),(4,5),(4,6),(4,8)}
These dice will give a sum of 2 with N={(1,1)}, which only has 1 combination
Thus, the probability of rolling a sum of 2 with these dice is