2:1/4=2* 4/1=2*4= 8 is the answer
a: b/c = a * c/b=a*c/b
Answer: 48 degrees-------------------------------------------------------
See the attached image for a visual of the problem and answer.
Based on the diagram, we have angle AHB = 132 degrees (given) equal in measure to angle XHY since these two angles are vertical angles.
Angles HYC and HXC are right angles due to the nature of AX and BY being altitudes. Recall that altitudes are segments that go from one vertex to the opposite side and they are perpendicular to the opposite side.
Focus on quadrilateral HXCY. So far, we know that...
Angle XHY = 132 degrees
Angle HYC = 90 degrees
Angle HXC = 90 degrees
The angle we want to find is angle ACB, which is the same as angle YCX. This angle is the missing angle of the quadrilateral HXCY.
For any quadrilateral, the four angles must add to 360 degrees.
(angle XHY) + (angle HYC) + (angle HXC) + (angle YCX) = 360
(132) + (90) + (90) + (angle YCX) = 360
312 + (angle YCX) = 360
312 + (angle YCX) - 312 = 360 - 312
angle YCX = 48 degrees
Since angle ACB is the same as angle YCX, we can say
angle ACB = angle YCX = 48 degrees
So in summary,
angle ACB = 48 degrees
<em>Part A: </em>
Let c represent the total amount of chocolate there is in lbs.
c = 0.25c + 0.75c
<em>Part B: </em>
0.75c represents milk chocolate, and we know that there are 3 lbs of milk chocolate, so you can replace the 0.75c with 3 (representing 3 lbs):
c = 0.25c + 3
Divide all the terms by c:
1 = 0.25 + 3/c
Subtract 0.25 from both sides to combine the like terms:
0.75 = 3/c
Multiply all the terms by c to make the equation easier to work with:
0.75c = 3
Divide both sides by 0.75 to isolate the c and find the total amount of chocolate in pounds.
c = 4
Substitute c for 4 in the term that defines dark chocolate (which was 0.25c)
0.25(4) = 1 pound
Therefore, there was exactly 1 pound of dark chocolate present in the chocolate.
This makes sense, as 1 pound of dark chocolate + 3 pounds of milk chocolate = 4 pounds of chocolate in total, and 1 is 25% of 4 and 3 is 75% of 4.
Answer:
D < 40.2 inches
Step-by-step explanation:
The maximum width of the TV must be 36 inches. Since TVs are approximately twice as wide as they are tall, the maximum height is 18 inches.
The diagonal of a TV can be determined as a function of its width (w) and height (h) as follows:

Therefore, the diagonal must be at most 40.2 inches.
Since the answer choices were not provided with the question, you should choose the biggest value that is under 40.2 inches.
A) y = -3
B) y = x + 3
C) x = -5
D) y = -2/1x -4