Answer:yes
Step-by-step explanation:
Answer:
2nd Account has $19,000
1st Account has $42,000
Step-by-step explanation:
First let's split the money invested.
x is money in account 1
y is money in account 2
1st equation
<u>$61,000=x+y</u>
5%=0.05
7%=0.07
2nd equation
<u>0.05*x+0.07*y=$3,430</u>
x=61,000-y
substitute into 2nd equation
0.05(61,000-y)+0.07y=3430
Solve.
3050-0.05y+0.07y=3430
0.02y=3430-3050
0.02y=380
y=380/0.02
y=$19,000
There are 2(two) ways to solve for the 1st account, but I will do it the long way.
y=61,000-x
substitute into 2nd equation
0.07(61,000-x)+0.05x=3430
Solve.
4270-0.07x+0.05x=3430
-0.02x=3430-4270
-0.02x=-840
x=-840/-0.02
x=$42,000
The short way...
x=61,000-y
x=61,000-19,000
x=$42,000
Hello! So for this question, all you have to do is add the numbers up to get the total cost. Groceries were $102.34 and the new shoes were $53.36. 102.34 + 53.36 = 155.7. Lorena spent $155.70 total.
Answer:
Step-by-step explanation:
a + 11s = 124.......a = 124 - 11s
4a + 10s = 122
4(124 - 11s) + 10s = 122
496 - 44s + 10s = 122
-44s + 10s = 122 - 496
-34s = -374
s = -374 / -34
s = 11 <==== student tickets cost $ 11
a + 11s = 124
a + 11(11) = 124
a + 121 = 124
a = 124 - 121
a = 3 <=== adult tickets cost $ 3
X^2-2x-5=(x-1)^2-6
After substituting we get that the domain is:
{-6;-5}