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2 years ago

What is the equation of the line that is parallel to the

Mathematics

1 answer:

Ipatiy [6.2K]2 years ago

6 0

Answer:

y = -1/3x -2

Step-by-step explanation:

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Help please, I'll give brainliest to the first correct answer

ololo11 [35]

The answer is B I hope this helps and you have a great day! :D

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3 years ago

4 and 9/10 minus 2 and 2/5 = (in fractions)

Zinaida [17]

Answer:

3 mark me brainlest

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the unit rate 30 degree drop in 6 hours Show your work

Lynna [10]

The unit rate is 5 degrees per hour.

Further explanation:

Unit rate is how much any quantity changes in one unit of time. For this purpose the change in quantity is divided by the time taken for that change.

Given

$Change\ in\ temperature= C= 30\ degrees\\Time=t=6 hours\\So,\\Unit\ rate= \frac{C}{t}\\Putting\ the\ values\\=\frac{30}{6}\\=5\ degrees\ per\ hour$

The unit rate is 5 degrees per hour.

Keywords: Formulas, Unit rate

Learn more about unit rate at:

#LearnwithBrainly

7 0

3 years ago

Create and equivalent expression using the distributive property for 5(3s-2)

maxonik [38]

If I read your question right, an equivalent expression would be 15s-10 after distributing the 5.

3 0

3 years ago

A certain college graduate borrows $8000 to buy a car. The lender charges interest at an annual rate of 10%. Assuming that inter

MaRussiya [10]

Answer:

The payment is $k=\$3216.92$ .

Interest paid during the 3-year period is $I_{T}=\$1651.76$

Step-by-step explanation:

The Payment amount

We are going to use the formula below with $VP=\$8000, i=10\%$ and $n=3$ .

$k=\frac{VP}{[\frac{1-(1+i)^{-n}}{i}] } =\frac{8000}{[\frac{1-(1+0.1)^{-3}}{0.1}] }=3216.92$

Interest paid during the 3 year

First period

$I_{1}=VP*i=8000*0.1=800$

$CS_{1}=k-I_{1}=3216.92-800=2416.92$

$Balance_{1}=VP-CS_{1}=8000-2416.92=5583.08$

Second period

$I_{2}=B_{1}*i=5583.08*0.1=558.31$

$CS_{2}=k-I_{2}=3216.92-558.31=2648.61$

$Balance_{2}=VP-CS_{2}=5583.08-2648.61=2924.47$

Third period

$I_{3}=B_{2}*i=2924.47*0.1=292.45$

Sum of Interest paid during the 3 years

$I_{t}=I_{1}+I_{2}+I_{3}=800+558.31+292.45=1651.76$

5 0

3 years ago