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Gwar [14]
3 years ago
11

Lora's gymnastics class practices floor exercises every other day.The class practices on the balance beam every third day,and th

e uneven bars every fourth day.Today is march 10,and the class practiced all three events.How many more times,before June 1,will the class practice all three on the same day.
Mathematics
1 answer:
sladkih [1.3K]3 years ago
3 0
The 12th decades every other day every three days and four days all have 12 in common I think
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Pleaseeee helppp answer correctly !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!
ohaa [14]

Answer: 132 degree

Step-by-step explanation:

X + 48 = 180

X = 180 - 48

X = 132 degree

5 0
3 years ago
20 square root of 270 /4 square root of 3
OleMash [197]

Answer:

<u>The most simplified form is 15√10</u>

Step-by-step explanation:

1. Let's simplify the expression:

20√270 ÷ 4√3

20√9 * 30/  4√3 (√270 = √9 * 30)

60 √30/ 4√3

(60 √3 * √10) / 4√3 (√30 = √3 * √10)

60/4 √10 ( We cancel √3 in the numerator and in the denominator)

15√10

<u>The most simplified form is 15√10</u>

6 0
3 years ago
Find cos B, sinB,tanb
emmasim [6.3K]

Using right triangle relations, we will get:

  • tan(B) = 1.05
  • sin(B) = 0.735
  • cos(B) =  0.7

<h3>How to find the value of the trigonometric equations?</h3>

We assume that bot triangles are equivalent, then the angle B will be the same as the angle Z.

Now remember the relations:

  • tan(θ) = (opposite cathetus)/(adjacent cathetus).
  • sin(θ) = (opposite cathetus)/(hypotenuse)
  • cos(θ) = (adjacent cathetus)/(hypotenuse).

If we step on angle B, we have:

  • opposite cathetus = 29.4
  • adjacent cathetus = 28
  • hypotenuse = 40.6

Replacing that, we get:

  • tan(B) = 29.4/28 = 1.05
  • sin(B) = 29.4/40.6 = 0.735
  • cos(B) = 28/40.6 = 0.7

If you want to learn more about trigonometric functions:

brainly.com/question/8120556

#SPJ1

6 0
2 years ago
Three consecutive integers sum to 6. What is the least of these integers?
dexar [7]

Answer:

The least of the three integers is 1.

Step-by-step explanation:

Hi there!

Let <em>x</em> be equal to the least of these integers.

Let <em>x</em>+1 and <em>x</em>+2 be the next consecutive integers.

We're given that these integers have a sum os 6.

We can use these to construct an equation:

(x)+(x+1)+(x+2)=6

Combine like terms:

x+x+1+x+2=6\\x+x+x+1+2=6\\3x+3=6\\3x=3\\x=1

Therefore, the least of these integers is 1.

The other two integers would be 2 and 3.

I hope this helps!

3 0
3 years ago
Solve the system of equations<br> -5x+13y+-7<br> 5x+4y=24<br> y=<br> x=
aleksklad [387]
<h3>The value of y is equal to 1.</h3><h3>The value of x is equal to 4.</h3>

Because both equations have a term that will cancel out if they're added together, we're going to add both equations together.

-5x + 5x = 0

13y + 4y = 17y

-7 + 24 = 17

17y = 17

Divide both sides by 17.

y = 1

Now that we have a constant value of y, we can solve for x.

-5x + 13(1) = -7

-5x + 13 = -7

Subtract 13 from both sides.

-5x = -20

Divide both sides by -5.

x = 4


3 0
3 years ago
Read 2 more answers
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