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2 years ago

Is x=-4 and y=3 a solution of the equation 2x -5y=-23

Mathematics

2 answers:

pishuonlain [190]2 years ago

7 0

Answer:

Yes

Step-by-step explanation:

First you pull them into the equation

2(-4)-5(3)=-23

Distribute

-8-15=-23

-23=-23

Mamont248 [21]2 years ago

4 0

Is x=-4 and y=3 a solution of the equation 2x -5y=-23

2x -5y=-23
2(-4) - 5(3) =-23
-8 - 15 = -23
-23 = -23

Therefore, x = 4 and y = 3 is a solution to 2x -5y=-23.

Hope that helps!

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Identify an equation in point-slope form for the line perpendicular to

Alchen [17]

Answer:

$y - 9 = \frac{1}{2}(x +3)$

Step-by-step explanation:

Given

Function; $y = -2x + 8$

Required

Find an equation perpendicular to the given function if it passes through (-3,9)

First, we need to determine the slope of: $y = -2x + 8$

The slope intercept of an equation is in form;

$y = mx + b$

Where m represent the slope

Comparing $y = m_1x + b$ to $y = -2x + 8$ ;

We'll have that

$m_1 = -2$

Going from there; we need to calculate the slope of the parallel line

The condition for parallel line is;

$m_1 * m_2 = -1$

Substitute $m_1 = -2$

$(-2) * m_2 = -1$

Divide both sides by -2

$m_2 =\frac{ -1}{-2}$

$m_2 =\frac{1}{2}$

The point slope form of a line is;

$y - y_1 = m_2(x - x_1)$

Where $(x_1,y_1) = (-3,9)$ and $m_2 =\frac{1}{2}$

$y - y_1 = m_2(x - x_1)$ becomes

$y - 9 = \frac{1}{2}(x - (-3))$

Open the inner bracket

$y - 9 = \frac{1}{2}(x +3)$

Hence, the point slope form of the perpendicular line is: 

 $y - 9 = \frac{1}{2}(x +3)$ 

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3 years ago

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3 years ago

the height of a triangle is three times its base the base of the triangle is 6 inches what is the area in square inches of the t

nirvana33 [79]

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Determine whether the number could be the probability of an event. Explain your reasoning. -0.25

mr Goodwill [35]

yo sup??

The number can't be a probability of an event cause probability of an even lied between 0 and 1 whereas the number given to use is -0.25.

Since probability can't be negative therefore it isn't a probability of an event.

Hope this helps.

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3 years ago