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Vanyuwa [196]
3 years ago
8

Find the area of the shaded region:

Mathematics
2 answers:
koban [17]3 years ago
6 0

Find the area of the circle:

Area = PI x r^2

Area = 3.14 x 9^2

Area = 3.14 x 81

Area = 254.34 square cm

Now multiply the area of the circle by the shaded portion which is the fraction of the degree over 360 degrees:

254.34 x 80/360 = 20,347.2/360 = 56.52

The shaded area is 56.52 square cm.

Dmitriy789 [7]3 years ago
3 0

Area of circle formula: A = πr²

A = π(9)²

A = 81π

A = 254.34cm²

The ratio of degrees in the shaded region to total degrees in a circle:

80/360 = 40/180 = 20/90 = 10/45 = 2/9

Multiply:

254.34/1 * 2/9

508.68/9

56.52

Therefore, the area of the shaded region is 56.52cm²

Best of Luck!

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Answer:

Part A:

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Median value is depicted on a box plot by the vertical line that divides the rectangular box. Therefore:

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It takes a hose 2 minutes to fill a rectangular aquarium 12 inches long, 13 inches wide, and 14 inches tall. How long will it ta
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The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2885 and standard deviation
aliina [53]

Answer:

a.  X~N(2,885, 651)

b.  0.086291

c.  0.00058

d.  3213.10 calories

Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

-Let X a random variable denoting  the number of calories consumed.

-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

b. The probability that less than 2000 calories are consumed is calculated using the formula:

P(X

#substitute the given values in the formula to solve for P:

P(X

Hence, the probability of consuming less than 2000 calories is 0.08691

c. The proportion of customers consuming more than 5000 calories is calculated as:

P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058

Hence, the proportion of customers consuming over  5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

-We equate this to the formula to solve for the mean consumption:

0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

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Answer:

x ≥ -1

Step-by-step explanation:

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