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gregori [183]
3 years ago
8

Use the graph below to fill in the blank with the correct number: f(1) = _______

Mathematics
1 answer:
lions [1.4K]3 years ago
5 0
F (1) = -2
hope this helps :)
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Given two different circles O and Q, which of the following cases presents two circles with no (zero) common tangents?
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Select all of the values of
omeli [17]

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gmkyhmfnggnjggfbvmhfjxxjyyjyjhchhfxg

Step-by-step explanation:

8 0
3 years ago
a family has five children. the probability of having a girl is 1/2. whats probability of having at leasr 4 girls g'
Dima020 [189]

Answer:

Probability of having at least 4 Girls

= 0.6875

Step-by-step explanation:

Probability of having at least 4 Girls is 1-probability of having exactly 3 girls

Total number of children= 5 = N

Probability of having a girl p = 0.5

Probability of not having a girl q= 0.5

X= 3

Probability of at least 4 girls is given by

Probability= NCX(p)^x(q)^(N-x)

Probability = 5C3(0.5)^3(0.5)^(5-3)

Probability = 5C3(0.5)^3(0.5)^2

Probability= 5!/3!2!(0.5)^3(0.5)^2

Probability= 10(0.125)(0.25)

Probability= 0.3125

Probability of having at least 4 Girls

= 1- 0.3125

= 0.6875

7 0
2 years ago
An instructor who taught two sections of engineering statistics last term, the first with 20 students and the second with 30, de
Lelechka [254]

Answer:

(a) P(X=10) = 0.2070

(b) P(X\geq 10) = 0.3798

Step-by-step explanation:

Note that in this problem we have an initial population N = 50, of which 30 fulfill a certain characteristic "m" (belong to the second section). Then, from the population N, a sample of size n = 15 is selected and it is desired to know how many comply with the desired characteristic (second section).

So

Let X be the number of projects in the second section, then X is a discrete random variable that can be modeled by a hypergeometric distribution.

(a)

Therefore, to answer question (a) we use the following equation presented in the attached image:

Where:

N = 50\\m = 30\\n = 15\\X = 10

Then:

P (X = 10) = \frac{\frac{30!}{10!(30-10)!}\frac{20!}{5!(20-5)!}}{\frac{50!}{15!(50-15)!}}\\\\\\P(X=10) = 0.2070

(b)

For part (b) we have:

P(X\geq10) = 1-P(X

P(X\geq 10) = 1-0.6202 \\\\P(X\geq 10) = 0.3798

4 0
3 years ago
ANYONE PLEASE HELP ME I REALLY NEED THE ANSWER RIGHT NOW I HOPE Y'ALL CAN HELP ME:(
ratelena [41]

Answer:

I think the first one is power ( if not then coefficient) and the second is definitely expression

Step-by-step explanation:

6 0
2 years ago
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