N = population size
n = sample size
sigma = population standard deviation
xbar = sample mean
SE = standard error
fpc = finite population correction
In this case,
N = 200
n = 49
sigma = 14
xbar = 56
Since n/N = 49/200 = 0.245 is larger than 0.05, this means we must use a finite population correction factor. I'll use fpc in place of 'finite population correction'.
If we ignore the fpc, then the SE would be simply sigma/sqrt(n) = 14/sqrt(49) = 2.
However we cannot ignore the fpc. We must use it due to the fact that n/N > 0.05.
--------------------------
Let's compute the fpc factor
fpc = sqrt((N-n)/(N-1))
fpc = sqrt((200-49)/(200-1))
fpc = 0.87108780834612
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With the fpc factor, we'll have the true SE to be SE = fpc*sigma/sqrt(n) = 0.87108780834612*14/sqrt(49) = 1.74217561669224
The final answer, accurate to 6 decimal places, is therefore 1.742176
Idk that answer i just wants to finish mi profile
Answer:
a=4
Step-by-step explanation:
4(2+a)=24
8+4a=24
4a=24-8
a=16/4
a=4
Answer: -6
Step-by-step explanation: 7 + -6 = 1
:\
Answer:
X=12
Step-by-step explanation:
I did this in my head but if you need the explaination tell me in the comments.
