Answer:
<h2>This equation has no natural roots.</h2>
Step-by-step explanation:

Answer:
180/t = r
Step-by-step explanation:
In this question, we would have to write an equation that represents the scenario given.
We know that the car traveled 180 miles at a constant rate.
We would use the y = mx + b format for the equation, but replacing the variables with "r" and "t"
We know that 180 will be our y-variable, since that would be the base of the equation:
180 = ???
And to find how long/fast it will take the car, we would need to multiply the rate of speed "r" and time "t" in order to get our distance.
Plug it into the equation:
180 = rt
With this set up, you can find the rate of speed of the car when you know the time.
You would simply solve it as:
180/t = r
Let x represent the days it will take for the stalk to be at least 300 cm tall
3x+9≥300
3x≥291
x≥97
Answer:
7.3% of the bearings produced will not be acceptable
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.
So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.
Larger than 0.504
1 subtracted by the pvalue of Z when X = 0.504.



has a pvalue of 0.9938
1 - 0.9938= 0.0062
Smaller than 0.496
pvalue of Z when X = -1.5



has a pvalue of 0.0668
0.0668 + 0.0062 = 0.073
7.3% of the bearings produced will not be acceptable