Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
Answer:
Jack in Zeta Labs near Facility Intelligence and Zeta Labs spawn (Sells gadgets like the Presence Reduction Module and Night Vision Goggles)
Step-by-step explanation:
She has extra because she only wants to make 80oz and it takes 8 and she has 30 so 30 is extra
Answer: 
Step-by-step explanation:
You have the equation 
.
Then, to solve for the variable 
from the equation you need:
Make the subtraction of the right side of the equation:
(As the denominators are 1 and 
, the least common denominator is )
Multiply to both sides:
Add 
to both sides:
And finally divide both sides by 
:
Answer:
C=14pi cm
A=49pi cm^2
Step-by-step explanation:
1) Circumference of a circle is 2piR and R=7cm
C=2pi(7)
C=14pi cm
2) Area of a circle is piR^2 and R=7cm
A=pi (7)^2
A=49pi cm^2
