PLEASE HELP

Mathematics

1 answer:

liberstina [14]3 years ago

5 0

Answer:

Step-by-step explanation:

check the above attachment to verify the answer.

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Find the range of the function. f(x)=10-x^2

Ratling [72]

Answer:

range = x ≤ 10

Step-by-step explanation:

Given in the question the function

f(x)=10-x^2

The range of a function is the complete set of all possible resulting values of the dependent variable F(x) after we have substituted the domain which is the values of x.

domain = set of all integers

range = x ≤ 10

f(x)=10-x²

since any negative value of x will be positive with squared so we will start from 0

f(0) = 10-0² = 10

f(1) = 10 - 1² = 9 = f(-1) = 10 -(-1)²

....and so on.

5 0

3 years ago

There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t

beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways $=(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})$