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vazorg [7]
2 years ago
11

Which expression is equivalent to 22y+11?

Mathematics
2 answers:
dalvyx [7]2 years ago
7 0

Step-by-step explanation:

11(2y+1)

hope it helps.....

STALIN [3.7K]2 years ago
5 0
22. (2y). Cs it feels right
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valina [46]

Answer:

5d×(d-4)

-20d answer

answer -20d

3 0
3 years ago
What is 6x3/5 as a mixed number
Katen [24]
First, make 6 into an improper fraction.
6/1
Now multiply the numerators.
6x3=18
Now, the same with the denominators.
1x5=5
18/5
Now make it into a mixed number.
5x3=15
3 and...
18-15=3
3 and 3/5!!
Hope this helped!
8 0
3 years ago
Find the sequence 3n-1
aivan3 [116]

a(1) = 3(1)-1 = 3-1 = 2

a(2) = 3(2)-1 = 6-1 = 5

a(3) = 3(3)-1 = 9-1 = 8

So, the sequence would be 2,5,8,11....

6 0
3 years ago
An online retailer offers next-day shipping for an extra fee. The retailer says that 95% of customers who pay for
alekssr [168]

Answer:

Step-by-step explanation:

4 0
2 years ago
I don’t understand this help please
Elodia [21]

Answer:

  9

Step-by-step explanation:

The first simplification we can make is to replace 6^0 with 1.

The first rules of exponents we can apply are ...

  <em>(a·b)^c = a^c·b^c</em> . . . . . . similar to the distributive property

<em>   (a^b)^c = a^(b·c)</em>

This reduces your expression to ...

  (2^8\cdot 3^{-5})^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot 2^{28}=2^{8(-2)}\cdot 3^{-5(-2)}\cdot\dfrac{3^{-2(4)}}{2^{3(4)}}\cdot 2^{28}\\\\=2^{-16}\cdot 3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot 2^{28}

Now we can apply another two rules of exponents:

<em>   (a^b)(a^c) = a^(b+c)</em>

<em>   1/a^b = a^-b</em>

Using these, we have ...

  =2^{-16-12+28}\cdot 3^{10-8}\\\\=2^0\cdot 3^2\\\\=1\cdot 9=9

The value of the expression is 9.

3 0
3 years ago
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