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andrezito [222]
3 years ago
9

Can someone help me with this? Please and thank you!

Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0

Answer:

She should find the squares between 4.2 and 4.3

Step-by-step explanation:

The square of 4.2 was too low and the square for 4.3 was too high so the answer is between the two.

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Write the ratio of corresponding sides for the similar triangles and reduce the ratio to lowest terms.
Whitepunk [10]

The ratio of the sides of the given similar triangles is: C. 4/12 = 5/15 = 1/3.

<h3>How do the Sides of Similar Triangles Relate?</h3>

The corresponding sides of similar triangles have ratios that are equal to each other.

The corresponding sides and their ratios are:

4/12 = 1/3

5/15 = 1/3

Therefore, the ratio of their sides in its lowest term is:

C. 4/12 = 5/15 = 1/3

Learn more about the similar triangles on:

brainly.com/question/2644832

#SPJ1

4 0
2 years ago
Please help asap!!
ElenaW [278]

Answer:

ok sorry let me try to figure this one out because i dont kow how to do a tree diagram on here

Step-by-step explanation:

6 0
3 years ago
3+7+11+15+19+23+27<br>1.t1=<br>s1=<br>express t1 in terms of s1​
icang [17]
So it would be 3s + 7s + 11s + 15s + 19s + 23s + 27s. Hope this helps
8 0
3 years ago
If the following fraction is reduced, what will be the exponent on the p? -5p^5q^4/ 8p^2q^2
viktelen [127]
<span>-5p^5q^4/ 8p^2q^2
= -5p^3q^2

</span><span>exponent on the p will be 3

answer
</span><span>C.3</span>
6 0
3 years ago
Read 2 more answers
A poll found that 53% of a sample of 1170 teens in a certain large country go online several times a day. (Treat this sample as
posledela

Answer:(a) margin error = 2.4%

(b) The margin error gives the measure in percentage of how the population parameter determined differ from the real population statistics or value.

(c) in 90% of the samples of teens in the country, the percent who go online several times a day will be within 50.6% and 55.4%. of the estimated 100%

Step-by-step explanation:

Using the proportion formulae

Margin error = z √p(1-p)/n

n= 1170, p = 53% = 0.53, 1-p = 0.47

and the z value at 90% C.I = 1.645

M error= 1.645 √0.53×0.47/1170

Margin error = 0.024 = 0.024 ×100

Margin error = 2.4%

53 - 2.4 = 50.6% and 53 + 2.4 = 55.4%

In other words 90% of the time: the number of teens who go online several time a day will be between 50.6 and 55.4%.

8 0
3 years ago
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