No solution of the system of equations y = -2x + 5 and -5y = 10x + 20 ⇒ 2nd answer
Step-by-step explanation:
Let us revise the types of solutions of a system of linear equations
- One solution
- No solution when the coefficients of x and y in the two equations are equal and the numerical terms are different
- Infinitely many solutions when the coefficients of x , y and the numerical terms are equal in the two equations
∵ y = -2x + 5
- Add 2x to both sides
∴ 2x + y = 5 ⇒ (1)
∵ -5y = 10x + 20
- Subtract 10x from both sides
∴ -10x - 5y = 20
- Divide both sides by -5
∴ 2x + y = -4 ⇒ (2)
∵ The coefficient of x in equation (1) is 2
∵ The coefficient of x in equation (2) is 2
∴ The coefficients of x in the two equations are equal
∵ The coefficient of y in equation (1) is 1
∵ The coefficient of y in equation (2) is 1
∴ The coefficients of y in the two equations are equal
∵ The numerical term in equation (1) is 5
∵ The numerical term in equation (2) is -4
∴ The numerical terms are different
From the 2nd rule above
∴ No solution of the system of equations
No solution of the system of equations y = -2x + 5 and -5y = 10x + 20
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You can learn more about the system of equations in brainly.com/question/6075514
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Didn't you already get this question right because it says 1/1 point?
A)
no solutionB)
infinite solutionsC)
x = -36D)
x = 0
has infinite solutions, which is your answer.
<span>(7y2 + 6xy) – (–2xy + 3)
7y^2 + 6xy +2xy +3
7y^2 +8xy +3
8xy + 7y^2 +3</span>
Answer:
Equal to
Step-by-step explanation:
I hope this helped
3 thousandths: 0.003
2 hundreths: 0.02
0.003+0.02= 0.023