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2 years ago

7

If y varies directly as x and y = -18 and x = 3, find x when y = 30.

2 answers:

Eddi Din [679]2 years ago

6 0

Answer:

x = - 5

Step-by-step explanation:

Given y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = - 18 when x = 3 , then

- 18 = 3k ( divide both sides by 3 )

- 6 = k

y = -6x ← equation of variation

When y = 30 , then

30 = - 6x ( divide both sides by - 6 )

- 5 = x

Otrada [13]2 years ago

3 0

Answer:

$y \: varies \: directly \: as \: x \: mean \\ \: y \: increase \: or \: decrease \: with \: x \\ y = - 18 \: \: \: \: x = 3 \\ y = 30 \: \: \: x = ? \\ - 18 ? = 90 \\ ? = - 5 = x$

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2 years ago

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<h2><u>Finding the value</u></h2>

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The simple interest on a certain sum of money for 2 years at 5% per annum is Rs 320. What will be the compound interest on the s

Brilliant_brown [7]

Answer:

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Step-by-step explanation:

Find the <u>principal</u> amount invested.

<u>Simple Interest Formula</u>

I = Prt

where:

I = interest earned
P = principal
r = interest rate (in decimal form)
t = time (in years)

Given:

I = Rs 320
r = 5% = 0.05
t = 2 years

Substitute the given values into the formula and solve for P:

⇒ 320 = P(0.05)(2)

⇒ 320 = P(0.1)

⇒ P = 3200

<u>Compound Interest Formula</u>

$\large \text{$ \sf I=P\left(1+\frac{r}{n}\right)^{nt} -P$}$

where:

I = interest earned
P = principal amount
r = interest rate (in decimal form)
n = number of times interest applied per time period
t = number of time periods elapsed

Given:

P = 3200
r = 5% = 0.05
n = 1 (annually)
t = 2 years

Substitute the given values into the formula and solve for I:

$\implies \sf I=3200\left(1+\frac{0.05}{1}\right)^{2} -3200$

$\implies \sf I=3200\left(1.05\right)^{2} -3200$

$\implies \sf I=3200\left(1.1025\right) -3200$

$\implies \sf I=3528-3200$

$\implies \sf I=328$

Therefore, the compound interest on the same sum for the same time at the same rate is Rs 328.

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