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AlexFokin [52]
2 years ago
9

The periodic table is organized into vertical groups of:.

Chemistry
1 answer:
lapo4ka [179]2 years ago
5 0
The vertical columns on the periodic table are called groups or families
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Resources that are not able to be reproduced as quickly as they are used are called _____.
Maurinko [17]

Answer:

C) non renewable resources

Explanation:

These are resources such as oil that are formed over a long period of time but are consumed very quickly.

8 0
3 years ago
What is the chemical formula for the binary compound composed of au3+ and i- ions?
Step2247 [10]
AuI3, or Gold Iodide.

Hope this helps! :)
8 0
3 years ago
What Group is this Element in?<br> O Group 3<br> O Group 4<br> O Group 7<br> Group 1
Bond [772]

Answer: group 7

Explanation:

7 0
3 years ago
The atomic mass of chlorine is 17 give the electron configuration for a neutral atom of chlorine
Nana76 [90]
1s²2s²2p⁶3s²3p⁵

Explanation:
In writing the first two electrons will go in the 1s orbital.
Since 1s can only hold two electrons the next 2 electrons for chlorine go in the 2s orbital. 
The next six electrons will go in the 2p orbital.
The p orbital can hold up to six electrons.
 We'll pull six in the 2p orbital  and then put the next two electrons in the 3s.
Since the 3s is now full we'll move to the 3p where we'll place the remaining five electrons.

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5 0
3 years ago
Consider the following reaction:2NOBr(g) 2NO(g) + Br2(g)If 0.412 moles of NOBr(g), 0.678 moles of NO, and 0.224 moles of Br2 are
Vaselesa [24]

Answer: K_c=0.0587M

Explanation: The given chemical reaction is:

2NOBr(g)\rightleftharpoons 2NO(g)+Br_2(g)

Equilibrium constant (Kc) in general is written as:

K_c=\frac{[products]}{[reactants]}

Note:- Coefficients are written as their powers

So, the Kc expression for the above reaction will be:

K_c=\frac{[NO]^2[Br_2]}{[NOBr]^2}

Equilibrium moles are given for all of them. Let's divide the moles by given liters to get the concentrations.

[NOBr]=\frac{0.412mol}{10.3L}   = 0.040 M

[NO]=\frac{0.678mol}{10.3L}   = 0.0658 M

[Br_2]=\frac{0.224mol}{10.3L}   = 0.0217 M

Plug in the values in the equilibrium expression to calculate Kc.

K_c=\frac{(0.0658M)^2(0.0217M)}{(0.040M)^2}

K_c=0.0587M

4 0
3 years ago
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