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saveliy_v [14]
3 years ago
14

The atomic mass of chlorine is 17 give the electron configuration for a neutral atom of chlorine

Chemistry
1 answer:
Nana76 [90]3 years ago
5 0
1s²2s²2p⁶3s²3p⁵

Explanation:
In writing the first two electrons will go in the 1s orbital.
Since 1s can only hold two electrons the next 2 electrons for chlorine go in the 2s orbital. 
The next six electrons will go in the 2p orbital.
The p orbital can hold up to six electrons.
 We'll pull six in the 2p orbital  and then put the next two electrons in the 3s.
Since the 3s is now full we'll move to the 3p where we'll place the remaining five electrons.

 Hope this helped ;)
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What is the final volume (L) of a 1.00 L system at 315 K and 1.10 atm if STP conditions are established?
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Answer:

0.95L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 1L

T1 (initial temperature) = 315K

P1 (initial pressure) = 1.10 atm

T2 (final temperature) = stp = 273K

P2 (final pressure) = stp = 1atm

V2 (final volume) =?

Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the system can be obtained as follow:

P1V1/T1 = P2V2/T2

1.1 x 1/315 = 1 x V2/273

Cross multiply to express in linear form.

315 x V2 = 1.1 x 273

Divide both side by 315

V2 = (1.1 x 273) /315

V2 = 0.95L

Therefore, the final volume of the system if STP conditions are established is 0.95L

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Explanation:

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Paha777 [63]

Answer:

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How do we calculate pressure?

Pressure of any gas will be calculated by using the ideal gas equation as:

PV = nRT, where

P = pressure of gas = ?

V = volume of gas = 50L

R = universal gas constant = 0.082 L.atm/K.mol

T = temperature of gas = -14.5°C = 258.65 K

n is moles of gas and it will be calculated as:

n = W/M, where

W = given mass of CO₂ = 66g

M = molar mass of CO₂ = 44 g/mol

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On putting values we get

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P = 0.636 atm

Hence required pressure is 0.636 atm.

Explanation:

Hope This Helps

Have A Great Day

~Zero~

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