All categories

3 years ago

Resources that are not able to be reproduced as quickly as they are used are called _____.

Chemistry

1 answer:

Maurinko [17]3 years ago

8 0

Answer:

C) non renewable resources

Explanation:

These are resources such as oil that are formed over a long period of time but are consumed very quickly.

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If 588 grams of FeS2 is allowed to react with 352 grams of O2 according to the following equation, how many grams of Fe2O3 are p

Rainbow [258]

Answer: The mass of iron (III) oxide produced is 782.5 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For $FeS_2$ :

Given mass of $FeS_2$ = 588 g

Molar mass of $FeS_2$ = 120 g/mol

Putting values in equation 1, we get:

$\text{Moles of }FeS_2=\frac{588g}{120g/mol}=4.9mol$

For $O_2$ :

Given mass of $O_2$ = 352 g

Molar mass of $O_2$ = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of }O_2=\frac{352g}{32g/mol}=11mol$

The chemical equation for the reaction of $FeS_2$ and oxygen gas follows:

$FeS_2+O_2\rightarrow Fe_2O_3+SO_2$

By Stoichiometry of the reaction:

1 mole of $FeS_2$ reacts with 1 mole of oxygen gas

So, 4.9 moles of $FeS_2$ will react with = $\frac{1}{1}\times 4.9=4.9mol$ of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, $FeS_2$ is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of $FeS_2$ produces 1 mole of iron (III) oxide

So, 4.9 moles of $FeS_2$ will produce = $\frac{1}{1}\times 4.9=4.9moles$ of iron (III) oxide

Now, calculating the mass of iron (III) oxide from equation 1, we get:

Molar mass of iron (III) oxide = 159.7 g/mol

Moles of iron (III) oxide = 4.9 moles

Putting values in equation 1, we get:

$4.9mol=\frac{\text{Mass of iron (III) oxide}}{159.7g/mol}\\\\\text{Mass of iron (III) oxide}=(4.9mol\times 159.7g/mol)=782.5g$

Hence, the mass of iron (III) oxide produced is 782.5 grams

8 0

3 years ago

I WILL GIVE BRAINLIEST!!!!!!!!!!

oksano4ka [1.4K]

Hello.

HI + NaOH --> NaI + H2O

2HClO4 + Sr(OH)2 --> Sr(ClO4)2 + 2H2O

Have a nice day

7 0

4 years ago

Which layer of the earth is the coolest in temperature?

PilotLPTM [1.2K]

Answer:

B) Crust

Explanation:

It's the farthest layer from the core listed.

5 0

3 years ago

If an unknown quantity of gas is held at a temperature of 789 K in a container with a volume of

Orlov [11]

Answer:

n = 0.34 mol

Explanation:

Given data:

Given temperature = 789 K

Pressure = 765 torr ( 765/760 = 1.0 atm

Volume of container = 22.0 L

Number of moles of gas = ?

Solution:

Formula:

PV = nRT

n = PV/RT

n = 1.0 atm × 22.0 L / 0.0821 atm.L/mol.K ×789 K

n = 22.0 L.atm /64.8 atm.L/mol

n = 0.34 mol

8 0

3 years ago

How many moles are in 2.6 x 10 ^25 atoms of Li?

Cerrena [4.2K]

Answer:

43 mole

Explanation:

Given data:

Number of atoms of Li = 2.6× 10²⁵ atoms

Number of moles = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

2.6× 10²⁵ atoms × 1 mole / 6.022 × 10²³ atoms

0.43 × 10² mole

43 mole

5 0

3 years ago