Assuming she make no profit and no loss from the business.
Let the number of gallons of the $8 grade water used be x, that of the $3 grade water, y, and that of the $4.50 grade water be z, then:
x + y + z = 200 . . . (1)
8x + 3y + 4.5z = 200(5) = 1,000 . . . (2)
z = 2y . . . (3)
Putting equation (3) into equations (1) and (2), we have:
x + y + 2y = 200
or x + 3y = 200 . . . (4)
and
8x + 3y + 4.5(2y) = 1000
or 8x + 3y + 9y = 1000
or 8x + 12y = 1000 . . . (5)
Multiplying equation (4) by 4, we have:
4x + 12y = 800 . . . (6)
Subtracting equation (6) from equation (5), we have:
4x = 200
or x = 200 / 4 = 50
Substituting for x into equation (4), we have:
50 + 3y = 200
or 3y = 200 - 50 = 150
or y = 150 / 3 = 50
Substituting for z into equation (3) gives:
z = 2(50) = 100
Therefore, 50 gallons each of the $8 grade water and the $3 grade water should be used and 100 gallons of the $4.50 grade water.
Answer:
6*4 = 24
Step-by-step explanation:
Hopefully that helps, and you can write fractions as x/y.
(2x+9)+(x)=180
3x+9=180
-9 -9
3x=171
÷3 ÷3
x=57
<h3>
Answer:</h3>
- A) p = 5, one solution
- B) no solutions
- C) infinite solutions
<h3>
Step-by-step explanation:</h3>
A) Add 19-5p to each side of the equation:
... 10 = 2p
... 5 = p . . . . . divide by the coefficient of p
B) Subtract 5p from both sides of the equation:
... -9 = -19 . . . . . there is <em>no value of p</em> that will make this true. (No solution.)
C) Subtract 5p from both sides of the equation:
... -9 = -9 . . . . . this is true for <em>every value of p</em>. (Infinite solutions.)
Answer:
NONE
Step-by-step explanation:
There is no such thing as a triangle with three angles measuring 63 degrees each. On the other hand, an equilateral triangle has three equal angles measuring 60 degrees each.
Answer: NONE