Answer: Our required probability is 0.83.
Step-by-step explanation:
Since we have given that
Number of dices = 2
Number of fair dice = 1
Probability of getting a fair dice P(E₁) = 
Number of unfair dice = 1
Probability of getting a unfair dice P(E₂) = 
Probability of getting a 3 for the fair dice P(A|E₁)= 
Probability of getting a 3 for the unfair dice P(A|E₂) = 
So, we need to find the probability that the die he rolled is fair given that the outcome is 3.
So, we will use "Bayes theorem":

Hence, our required probability is 0.83.
Answer:
n = 4/7
Step-by-step explanation:
Step 1: Write equation
8 = 14n
Step 2: Divide both sides by 14
n = 8/14
Step 3: Simplify
n = 4/7
2/5 are girls, therefore 3/5 are boys
3/5 = 24
1/5 = 24 ÷ 3 = 8
2/5 = 8 x 2 = 16
Altogether = 16 + 24 = 40
24 - 1 6 = 8
There are 40 children altogether
There are 8 more boys than girls.
So x times y=3030
x and y=unknown
find the factors (factors of 6=2 and 3)
3030=2,3,5,101 so
two multiplication is
2 times 1515
3 times 1010
5 times 606
30 times 101
202 times 15
303 times 10
505 times 6
There are 5 letters
there are 5 possibilities for the first letter, and 4 possibilities for the second letter after the first letter is used up
so 5 * 4 = 20 possibilities