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goldfiish [28.3K]
2 years ago
6

Add: (3x2 - 5x + 6) + (9 - 8x - 4x2)

Mathematics
2 answers:
svetlana [45]2 years ago
7 0

Answer: E) -x^2-13x+15 .

Step-by-step explanation:

To add : (3x^2 - 5x + 6) + (9 - 8x - 4x^2)

=3x^2 - 5x + 6+ 9 - 8x - 4x^2

This can be re-written as :

3x^2-4x^2-5x-8x+6+9

Combine like terms as

=(3-4)x^2-(5+8)x+15\ \ [\because (-)(+)=(-)]\\\\=-x^2-13x+15

Therefore, (3x^2 - 5x + 6) + (9 - 8x - 4x^2)=-x^2-13x+15

Hence, the correct option is E) -x^2-13x+15 .

Stolb23 [73]2 years ago
4 0
Add: (3x2 - 5x + 6) + (9 - 8x - 4x2)
The givens should be arranged first before we can start answering.
    3x2 - 5x + 6 plus
   -4x2 - 8x + 9
= -x2  - 13x +15
Therefore, the answer to the question is E) -x2  - 13x +15

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fomenos
The value of 5 into 756 is .0066, or 0.66%. You can write this out as shown, and draw it out using traditional division.
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Find the measure of the arc for abc
Luda [366]

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124

Step-by-step explanation:

360 - (90+146) = 124

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2 years ago
Rectangle 1 has length x and width y. Rectangle 2 is made by multiplying each dimension of Rectangle 1 by a factor of k, where k
tresset_1 [31]

Answer:

a) Similar

b) Perimeter of rectangle 2 is k times the Perimeter of rectangle 1 (Proved Below)

c) Area of rectangle 2 is k^2 times the Area of rectangle 1 (Proved Below)

Step-by-step explanation:

Given:

Rectangle 1 has length = x

Rectangle 1 has width = y

Rectangle 2 has length = kx

Rectangle 2 has width = ky

(a) Are Rectangle 1 and Rectangle 2 similar? Why or why not?

Rectangle 1 and Rectangle 2 are similar because the angles of both rectangles are 90° and the sides of Rectangle 2 is k times the sides of Rectangle 1. So sides of both rectangles is equal to the ratio k.

(b) Write a paragraph proof to show that the perimeter of Rectangle 2 is k times the perimeter of Rectangle 1.

Perimeter of Rectangle = 2*(Length + Width)

Perimeter of Rectangle 1 = 2*(x+y) = 2x+2y

Perimeter of Rectangle 2 = 2*(kx+ky) = 2kx + 2ky

                                          = k(2x+2y)

                                          = k(Perimeter of Rectangle 1)

Hence proved that Perimeter of rectangle 2 is k times the perimeter of rectangle 1.

(c) Write a paragraph proof to show that the area of Rectangle 2 is k^2 times the area of Rectangle 1.

Area of Rectangle = Length * width

Area of Rectangle 1 = x * y

Area of Rectangle 2 = kx*ky

                                  = k^2 (xy)

                                  = k^2 (Area of rectangle 1)

Hence proved that area of rectangle 2 is k^2 times the area of rectangle 1.

4 0
3 years ago
WILL GIVE BRAINLIEST!!
VMariaS [17]

Answer:

A(-1,4)\to A''(-1,-1)

B(0,2)\to B''(1,0)

C(1,2)\to C''(1,1)

D(-2,4)\to D''(-1,2)

Step-by-step explanation:

The given trapezoid has vertices at A(−1,4), B(0,2), C(1,2) and D(2,4).

The transformation rule for 90° counterclockwise rotation is

(x,y)\to(-y,x)

This implies that:

A(-1,4)\to A'(-4,-1)

B(0,2)\to B'(-2,0)

C(1,2)\to C'(-2,1)

D(2,4)\to D'(-4,2)

This is followed by a translation 3 units to the right.

This also has the rule: (x,y)\to (x+3,y)

A'(-4,-1)\to A''(-1,-1)

B'(-2,0)\to B''(1,0)

C'(-2,1)\to C''(1,1)

D'(-4,2)\to D''(-1,2)

Therefore:

A(-1,4)\to A''(-1,-1)

B(0,2)\to B''(1,0)

C(1,2)\to C''(1,1)

D(-2,4)\to D''(-1,2)

3 0
3 years ago
Asap
adoni [48]
Lower Quartile-21
Upper Quartile-52
Interquartile Range- 31

Hope this helps !!
3 0
3 years ago
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